Answer:
= 6n - 3
Step-by-step explanation:
There is a common difference d between consecutive terms, that is
d = 9 - 3 = 15 - 9 = 21 - 15 = 6
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 3 and d = 6, then
= 3 + 6(n - 1) = 3 + 6n - 6 = 6n - 3
<u>Answer:</u>
The probability of rolling an even number and then an odd number is 
Option C is correct
<u>Solution:</u>
Given, You roll a six-sided die twice.
We have to find what is the probability of rolling an even number and then an odd number?
We know that, rolling single die two times is equivalent to two dice rolling at a time.
So, now, total possible outcomes = 6 x 6 = 36
And, number of favourable outcomes = 3 even on 1st die x 3 odd on 2nd die = 3 x 3 = 9
Then, probability = 
Hence, the probability of given condition is and option c is correct.
Both still have the same profit. $2 for sandwiches and $3 for wraps. The only reason why there is a difference in the total amount is the change in number of sandwich or wrap sold in a given month. Therefore, next month's total sale is higher than last month's total sale making it safe to assume that the sale of sandwich or wrap is higher than last month's sale.
{hope this helps}
It takes 42 cherries to make a cherry pie.
If a chef bought 444 cherries and you would like to know how many more cherries would the last pie need, you can calculate this using the following steps:
444 / 42 = 74 / 7 = 10 4/7 pies
4/7 * 42 = 24 cherries
42 - 24 = 18 more cherries
Result: The last pie would need 18 more cherries.
