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Ostrovityanka [42]
3 years ago
12

Can you someone help me

Mathematics
1 answer:
lord [1]3 years ago
4 0

(6,8) is the answer also this could be the answer too (6,2)

hope this helps

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Wet N' Dry camp provides water-based activities and ground sports activities for a
wolverine [178]

Answer:

  1. x+y≤80; x≥8; y≥5
  2. see attached for a graph
  3. Twenty campers are doing water-based activities and 40 campers are doing ground-based activities.

Step-by-step explanation:

1. Let x and y represent the numbers of campers doing water- and ground-based activities, respectively.

  x + y ≤ 80 . . . . . . a maximum of 80 campers can be accommodated

  x ≥ 8 . . . . . . . . . . a minimum of 8 campers should be water-based

  y ≥ 5 . . . . . . . . . . a minimum of 5 campers should be ground-based

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2. See the attachment for a graph. Possible outcomes are shaded red. The boundary lines of the shaded area are included in the possible outcomes.

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3. Twenty campers are doing water-based activities and 40 campers are doing ground-based activities.

5 0
3 years ago
Which of the following quadrilaterals have diagonals that bisect each other?
Taya2010 [7]

Answer:

All A. B. C. D.

Step-by-step explanation:

7 0
3 years ago
ASAP - 15 points
Reptile [31]

Answer:

A) 2b+24x

Step-by-step explanation:

7b+3x-5b+21x

7b-5b+3x+21x

2b+3x+21x

2b+24x

8 0
3 years ago
Which of the following is true for this graph? <br><br> Will give brainliest to correct answer.
Contact [7]

The answer is A. Slope is rise/run. According to the graph, you can trace out and see that it rises 1 and goes to the right 4 times. This means that it has a positive slope of 1/4. And the line crosses the y intercept at y = 3

So answer choice A is correct.

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3 years ago
Find the values of the sine, cosine, and tangent for ZA C A 36ft B <br> 24ft
Reptile [31]
<h2>Question:</h2>

Find the values of the sine, cosine, and tangent for ∠A

a. sin A = \frac{\sqrt{13} }{2},  cos A = \frac{\sqrt{13} }{3},  tan A = \frac{2 }{3}

b. sin A = 3\frac{\sqrt{13} }{13},  cos A = 2\frac{\sqrt{13} }{13},  tan A = \frac{3}{2}

c. sin A = \frac{\sqrt{13} }{3},  cos A = \frac{\sqrt{13} }{2},  tan A = \frac{3}{2}

d. sin A = 2\frac{\sqrt{13} }{13},  cos A = 3\frac{\sqrt{13} }{13},  tan A = \frac{2 }{3}

<h2>Answer:</h2>

d. sin A = 2\frac{\sqrt{13} }{13},  cos A = 3\frac{\sqrt{13} }{13},  tan A = \frac{2 }{3}

<h2>Step-by-step explanation:</h2>

The triangle for the question has been attached to this response.

As shown in the triangle;

AC = 36ft

BC = 24ft

ACB = 90°

To calculate the values of the sine, cosine, and tangent of ∠A;

<em>i. First calculate the value of the missing side AB.</em>

<em>Using Pythagoras' theorem;</em>

⇒ (AB)² = (AC)² + (BC)²

<em>Substitute the values of AC and BC</em>

⇒ (AB)² = (36)² + (24)²

<em>Solve for AB</em>

⇒ (AB)² = 1296 + 576

⇒ (AB)² = 1872

⇒ AB = \sqrt{1872}

⇒ AB = 12\sqrt{13} ft

From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of 12\sqrt{13} ft (43.27ft).

<em>ii. Calculate the sine of ∠A (i.e sin A)</em>

The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e

sin Ф = \frac{opposite}{hypotenuse}             -------------(i)

<em>In this case,</em>

Ф = A

opposite = 24ft (This is the opposite side to angle A)

hypotenuse = 12\sqrt{13} ft (This is the longest side of the triangle)

<em>Substitute these values into equation (i) as follows;</em>

sin A = \frac{24}{12\sqrt{13} }

sin A = \frac{2}{\sqrt{13}}

<em>Rationalize the result by multiplying both the numerator and denominator by </em>\sqrt{13}<em />

sin A = \frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }

sin A = \frac{2\sqrt{13} }{13}

<em>iii. Calculate the cosine of ∠A (i.e cos A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e

cos Ф = \frac{adjacent}{hypotenuse}             -------------(ii)

<em>In this case,</em>

Ф = A

adjacent = 36ft (This is the adjecent side to angle A)

hypotenuse = 12\sqrt{13} ft (This is the longest side of the triangle)

<em>Substitute these values into equation (ii) as follows;</em>

cos A = \frac{36}{12\sqrt{13} }

cos A = \frac{3}{\sqrt{13}}

<em>Rationalize the result by multiplying both the numerator and denominator by </em>\sqrt{13}<em />

cos A = \frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }

cos A = \frac{3\sqrt{13} }{13}

<em>iii. Calculate the tangent of ∠A (i.e tan A)</em>

The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e

tan Ф = \frac{opposite}{adjacent}             -------------(iii)

<em>In this case,</em>

Ф = A

opposite = 24 ft (This is the opposite side to angle A)

adjacent = 36 ft (This is the adjacent side to angle A)

<em>Substitute these values into equation (iii) as follows;</em>

tan A = \frac{24}{36}

tan A = \frac{2}{3}

6 0
3 years ago
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