What is the value for the domain when the range is -3

What is the circumference of a circle with a radius of 8.4 inches

Klio2033 [76]

Answer: 52.77876 in

Explanation: C=2πr=2·π·8.4≈52.77876 in

3 0

3 years ago

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

On the packaging for a triangular sail, the edge measurements for the sail are listed as 7 ft × 15 ft × 17 ft. Without unfurling

ASHA 777 [7]

Answer:

Shape of Triangular sail is Obtuse Angled Triangle.

Step-by-step explanation:

The triangle is obtuse since the sum of the squares of 2 sides are greater than the square of the third side. (Converse Pythagorean theorem) Hope this helps!

Given: Length of sides of triangular sail = 7 ft , 15 ft , 7 ft

To find: Shape of Sail .i.e., shape of triangle

We use a result which states that

if a , b , c are sides of triangle where c is greater then a & b.

now, if c² < a² + b² then triangle is Acute angled

if c² = a² + b² then triangle is Right angled

if c² > a² + b² then triangle is Obtuse angled

here a = 7 , b = 7 & c = 15

c² = 15² = 225

a² + b² = 7² + 7² = 49 + 49 = 98

since, c² > a² + b²

⇒ Triangle must be Obtuse Angled.

Therefore, Shape of Triangular sail is Obtuse Angled Triangle.

7 0

3 years ago

Read 2 more answers

If 5.7×10^k= 570,000, what is the value of k?

antiseptic1488 [7]

Answer:

5

Step-by-step explanation:

570000/5.7 is 100000

100000 is 10^5

6 0

3 years ago

The combined age of three relatives is 120 years. James is three times the age of Dan, and Paul is two time the sum of the ages

BaLLatris [955]

Answer:

Step-by-step explanation:

Let x represent Dan's age

3x be James'age

Paul 2(3x+x)=6x+2x

Suming all ages

x+3x+6x+2x=120

Solving for x

12x=120

x=10 (Dan's age)

3×=30 (James'age)

6×+2×=80(Paul's age)

8 0

4 years ago