Answer:
Thank you
Step-by-step explanation:
Answer
v=-35
explanation
add -4 and -31 to get v which is -35
Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
Answer:166
Step-by-step explanation:438x.38=166
438 being the total amount of students
.38 being the 38% involved (moved percentage two to the left to make it a decimal)
3x + 1 < 7...subtract 1 from both sides
3x < 7 - 1
3x < 6 ...divide both sides by 3
x < 6/3
x < 2
there will be an open circle on 2....because the problem has no equal sign...the line will be shaded to the left...because it is less then.
