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Flauer [41]
3 years ago
9

ASAP please help me I need this quick The question and answers are in the picture

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0

Answer:

9 in²

Step-by-step explanation:

Area of rectangle: length times width

Plug the numbers in.

4.5 * 2 = 9 in²

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3x + 5y = 27
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A two-digit locker combination has two nonzero digits and no digit is repeated in any combination.
zzz [600]

Answer:

Answer choice C

Step-by-step explanation:

Similarly to the previous problem, there are two possibilities. In the first possibility, the chance of picking a digit lower than 7 is 6/9 or 2/3, because there are 6 digits below 7 and 9 digits in total. In this scenario, the probability of the second digit being below 7 is 5/8, since one of the digits has already been taken. The probability here is 5/8*6/9=5/12. In the other scenario, the probability of picking a number higher than 7 is 3/9 or 1/3. In this scenario, the probability of picking below 7 for the second digit is 6/8 or 3/4, because one of the digits has not been taken. 3/9*6/8= 1/4. Adding these two together, you get 8/12=2/3, or answer choice C. Hope this helps!

7 0
4 years ago
Which function forms an arithmetic sequence when x = 1, 2, 3, ...?
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5 0
3 years ago
Read 2 more answers
Which product is negative? (Negative StartFraction 3 over 8 EndFraction) (Negative StartFraction 5 over 7 EndFraction) (one-four
nasty-shy [4]

Answer:

(D)\left(-\dfrac38\right)\left(-\dfrac57\right)\left(-\dfrac14\right)

Step-by-step explanation:

The given options are:

(A)\left(-\dfrac38\right)\left(-\dfrac57\right)\left(\dfrac14\right)\\(B)\left(\dfrac38\right)\left(-\dfrac57\right)\left(-\dfrac14\right)\\(C)\left(\dfrac38\right)\left(\dfrac57\right)\left(\dfrac14\right)\\(D)\left(-\dfrac38\right)\left(-\dfrac57\right)\left(-\dfrac14\right)

The key to determining which product is negative is to understand the rule of sign multiplication.

Now:

  • The product of even negative terms is positive
  • The product of odd negative terms is negative.
  • The product of positive will always be positive.

In Options A and B, the number of negative signs is even, therefore our result is positive.

In option C, all the terms are positive, therefore our result will be positive.

In Option D, the number of negative signs is odd, therefore our result is negative.

4 0
3 years ago
Read 2 more answers
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