Just do 18 divided by 6, and make your answer a negative. The answer is -3
Answer:
We are given order pairs (–9, –8), (–{(8, 4), (0, –2), (4, 8), (0, 8), (1, 2)}.
We need to remove in order to make the relation a function.
Step-by-step explanation:
Note: A relation is a function only if there is no any duplicate value of x coordinate for different values of y's of the given relation.
In the given order pairs, we can see that (0, –2) and (0, 8) order pairs has same x-coordinate 0.
So, we need to remove any one (0, –2) or (0, 8) to make the relation a function. hope this helps you :) god loves you :)
Multiply both sides of the second equation by 100 to get rid of the decimals:
0.05<em>n</em> + 0.10<em>d</em> = 1.50
==> 5<em>n</em> + 10<em>d</em> = 150
Multiply both sides of the first equation by -5:
<em>n</em> + <em>d</em> = 21
==> -5<em>n</em> - 5<em>d</em> = -105
Add the two equations together:
(5<em>n</em> + 10<em>d</em>) + (-5<em>n</em> - 5<em>d</em>) = 150 + (-105)
Notice that the terms containing <em>n</em> get eliminated and we can solve for <em>d</em> :
(5<em>n</em> - 5<em>n</em>) + (10<em>d</em> - 5<em>d</em>) = 150 - 105
5<em>d</em> = 45
<em>d</em> = 45/5 = 9
Plug this into either original equation to solve for <em>n</em>. Doing this with the first equation is easiest:
<em>n</em> + 9 = 21
<em>n</em> = 21 - 9 = 12
So Donna used 12 nickels and 9 dimes.
Answer:
<em>D. 5 for x less than or equal to 4, equals 2x for x between 4 and 6 including 6, and equals 4 for x greater than 6 Domain: All real number</em>s.
Step-by-step explanation:
Find the complete diagram attached
First we need to get the derivative of the functions
For the function f(x) = 5x - 6
Using the formula
If f(x) = axⁿ
f'(x) = naxⁿ⁻¹
For the function f(x) = 5x - 6
f'(x) = 1(5)x¹⁻¹
f'(x) = 5x⁰
f'(x) = 5
For the function f(x) =x²-2
f'(x) = 2x²⁻¹
f'(x) = 2x
For the function f(x) = 4x+10
f'(x) = 1(4)x¹⁻¹
f'(x) = 4x⁰
f'(x) = 4
Get the domain
The domain is the value of the input variable x for which the functions exists. For the functions given, the domain will be on all real numbers i.e the functions will exists for any value of x on the number line.
Hence Option D is correct
If you follow PEMDAS your answer would be 3.6.