Rewrite 2/20 : 1/40 as a unit rate

The cross-sectional areas of a triangular prism and a right cylinder are congruent. The triangular prism has a height of 5 units

Yanka [14]

Answer:

Step-by-step explanation:

The volume of the prism is not equal to the volume of the cylinder.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the cross sectional areas of a triangular prism and a right cylinder.

Volume of cylinder = cross sectional area * height = 3 * x = 3x

Volume of triangular prism = cross sectional area * height = 5 * x = 5x

The volume of the prism is not equal to the volume of the cylinder.

Find out more on equation at: brainly.com/question/2972832

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7 0

2 years ago

A local company wants to evaluate their quality of service by surveying their customers.

stich3 [128]

Answer: b. 0.98

Step-by-step explanation:

The formula to find the maximum error of the estimated mean :

$E=z^*\dfrac{\sigma}{\sqrt{n}}$ (1)

, where $\sigma$ = standard deviation

n= Sample size

z* = Critical z-value.

As per given , we have

$\sigma=5$

n=100

Critical value for 95% confidence interval = z*=1.96

Put these values in the formula (1), we get

$E=(1.96)\dfrac{5}{\sqrt{100}}$

$E=(1.96)\dfrac{5}{10}=0.98$

Hence, the maximum error of the estimated mean quality for a 95% level of confidence is 0.98.

Therefore , the correct answer is b. 0.98 .

6 0

2 years ago

Read 2 more answers

If f(x) = x3 – x2 – 3, which of the following is equal to g(x) = f(2 – x)?

Andru [333]

Answer:

-x^3+5x^2-8x+1, which is choice A

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Work Shown:

f(x) = x^3 - x^2 - 3

f(x) = (x)^3 - (x)^2 - 3

f(2-x) = (2-x)^3 - (2-x)^2 - 3 ................ see note 1 (below)

f(2-x) = (2-x)(2-x)^2 - (2-x)^2 - 3 ........... see note 2

f(2-x) = (2-x)(4-4x+x^2) - (4-4x+x^2) - 3 ..... see note 3

f(2-x) = -x^3+6x^2-12x+8 - (4-4x+x^2) - 3 ..... see note 4

f(2-x) = -x^3+6x^2-12x+8 - 4+4x-x^2 - 3 ....... see note 5

f(2-x) = -x^3+5x^2-8x+1

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note1: I replaced every copy of x with 2-x. Be careful to use parenthesis so that you go from x^3 to (2-x)^3, same for the x^2 term as well.

note2: The (2-x)^3 is like y^3 with y = 2-x. We can break up y^3 into y*y^2, so that means (2-x)^3 = (2-x)(2-x)^2

note3: (2-x)^2 expands out into 4-4x+x^2 as shown in figure 1 (attached image below). I used the box method for this and for note 4 as well. Each inner box or cell is the result of multiplying the outside terms. Example: in row1, column1 we have 2 times 2 = 4. You could use the FOIL rule or distribution property, but the box method is ideal so you don't lose track of terms.

note4: (2-x)(4-4x+x^2) turns into -x^3+6x^2-12x+8 when expanding everything out. See figure 2 (attached image below). Same story as note 3, but it's a bit more complicated.

note5: distribute the negative through to ALL the terms inside the parenthesis of (4-4x+x^2) to end up with -4+4x-x^2