All categories

2 years ago

4-[(x+3)/ ((x^2 +5x +6)/(x-2))]

Mathematics

1 answer:

Vinil7 [7]2 years ago

4 0

Answer:

3 + 4/(x+2)

Step-by-step explanation:

4-[(x+3)/ ((x^2 +5x +6)/(x-2))]=

4- [(x+3)*(x-2)/(x^2 +5x +6))]=

4- [(x+3)(x-2)/(x+3)(x+2)]=

4-(x-2)/(x+2)=

(4x+8-x+2)/(x+2)=

(3x+10)/(x+2)=

3 + 4/(x+2)

You might be interested in

The yoga instructor at Universe Fitness spent $1,925 on 200 items for the upcoming yoga seminar. He purchased yoga mats for $12.

Alex17521 [72]

Answer:

The auditing book is not accurate

Step-by-step explanation:

25($12.5)+50($8)+125($10)+= $1,925

$312.5 + $400 + $1,250 = $1,925

$1,962.5 not= to $1,925

4 0

3 years ago

In a positive correlation, __________.

Brut [27]

Im pretty sure its b

7 0

2 years ago

Percent of change from 115 to 338

MrRa [10]

Answer:

237 ⁹/23% change

Step-by-step explanation:

115=100%

337-155=273 which represents the increase

115=100

273=?

273×100÷115= 237 ⁹/23%

Answer =237⁹/23%

7 0

2 years ago

How you solve<br> -9+[b-8]=-5

sertanlavr [38]

your answer is B= 12 your welcome :)

8 0

3 years ago

Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

5 0

2 years ago