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iragen [17]
3 years ago
9

Please answer the question! It is optional to answer the one where you need to upload the graph but if you wanna help answer it

you can!

Mathematics
1 answer:
Ganezh [65]3 years ago
6 0
The answer is option 3
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dybincka [34]

Answer:

i

Step-by-step explanation:

5 0
3 years ago
Solve for x in each polygon?
In-s [12.5K]
Look the lesson up online. Sometimes there is an answer key
8 0
3 years ago
Marta told Maribel “The sum of fifty and half the number of oranges is the same as one-hundred-twenty.” Maribel wrote 50 (one-ha
IRINA_888 [86]

Answer:

Her error was that the half should have been multiplied by m, instead

50 + \frac{1}{2}m = 120

Step-by-step explanation:

Given

Base\ Amount = 50

Rate = 0.05

Days = n

So, we have:

Base\ Amount + Rate * days = 120

50 + \frac{1}{2}m = 120

Hence, the error in her workings is that she should have pre-inform her before God and man.

7 0
3 years ago
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The University of Texas at Austin has three times as many students enrolledas the University of Miami. The University of Califor
harina [27]

Answer:

University of Texas has 46,500 students, University of California has 34,000 students and University of Miami has 15,500 students.

Step-by-step explanation:

Represent Texas with T, Miami with M and California with C. With the given information, the following equations were obtained.

T = 3 × M

T – 3M = 0 ………………………….(i)

C = 3,000 + 2 × M

C – 2M = 3,000…………………..(ii)

T + C + M = 96,000…………….(iii)

By rearranging, we have:

1T + 0C – 3M = 0 ………………………….(i)

0T + 1C – 2M = 3,000…………………..(ii)

1T + 1C + 1M = 96,000………….…….(iii)

The Augmented Matrix is:

\left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right]\left[\begin{array}{ccc}T\\C\\M\end{array}\right] = \left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]

Making \left[\begin{array}{ccc}T\\C\\M\end{array}\right] the subject of the formula we have:

\left[\begin{array}{ccc}T\\C\\M\end{array}\right] = \frac{\left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]}{\left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right]}

Let’s say matrix A = \left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right], the inverse of matrix A = \left[\begin{array}{ccc}\frac{1}{2} &-\frac{1}{2} &\frac{1}{2} \\-\frac{1}{3} &\frac{2}{3} &\frac{1}{3} \\-\frac{1}{6} &-\frac{1}{6} &\frac{1}{6} \end{array}\right] is determined by the formula \frac{Adjoint(A)}{determinant(A)}. This can also be computed directly on a scientific calculator.

\left[\begin{array}{ccc}T\\C\\M\end{array}\right] = \left[\begin{array}{ccc}\frac{1}{2} &-\frac{1}{2} &\frac{1}{2} \\-\frac{1}{3} &\frac{2}{3} &\frac{1}{3} \\-\frac{1}{6} &-\frac{1}{6} &\frac{1}{6} \end{array}\right] \left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]

= \left[\begin{array}{ccc}46,500\\34,000\\15,500\end{array}\right]

T = 46,500

C = 34,000

M = 15,500

6 0
4 years ago
Read 2 more answers
Choose all of the linear equations that have no solution.
eduard
6x+1=2(x+3)+4x has no solution because if you simplify it you get 6x+1=6x+3 which can not have any solution, since anything you substitute for x will not give you a solution.
4x-1=4(x+3) also has no solution. if you simplify you get 4x-1=4x+3 so no value that you substitute for x will give you a solution
7 0
3 years ago
Read 2 more answers
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