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noname [10]
3 years ago
10

Un cubo de hielo de 80 g de masa y a una temperatura de –10 oC se deja caer dentro de un vaso de agua a 0 oC. Si no hay intercam

bio de calor con el exterior, ¿cuánta agua se solidifica sobre el hielo?
Physics
1 answer:
il63 [147K]3 years ago
7 0

Answer:

the answer is 187

Explanation:

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A train leaves the station heading south on the tracks. It takes 5 seconds to reach 50 miles per hour. It completes the entire 1
Musya8 [376]
Well, in order to figure out the answer is to divide until you figure out how many miles they went per second. If it takes 5 seconds to reach 50 miles per hour it took 10 seconds per every 10 miles meaning each mile took 1 second. (Not actually possible but the answer) So, If it finished a 100 mile trip in 2 hours it took an hour for 50 miles. If it took 1 hour for 50 miles divide 60/50 which gets you 1.2 so it took 1.2 miles per minute meaning the car went 120 miles per hour I believe. I hope this helps :)
8 0
3 years ago
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Help!! this makes no sense to me
bulgar [2K]
3 meters i’m pretty sure
8 0
2 years ago
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A copper wire 12 cm long and a mass of 16 g is in a magnetic field of 1.2 T oriented perpendicular to the wire. What current wou
Ugo [173]

Answer:

Current, I = 1.08 A

Explanation:

Given that,

Length of the copper wire, l = 12 cm = 0.12 m

Mass of the wire, m = 16 g = 0.016 kg

Magnetic field, B = 1.2 T

The magnetic field is oriented perpendicular to the wire. We need to find the current in the wire.

Magnetic force, F = BIL

Force of gravity, F' = mg

F' = F

BIL=mg

I=\dfrac{mg}{BL}

I=\dfrac{0.016\times 9.8}{1.2\times 0.12}

I = 1.08 A

So, the current through the wire is 1.08 A. Hence, this is the required solution.

8 0
4 years ago
Action-reaction forces do not cancel each other because the action force is always greater than the reaction force
mestny [16]
True hopefully that worked
3 0
3 years ago
The lead nucleus has a diameter of 14.2 fm. What is the electric field strength at the surface of a lead nucleus
Snowcat [4.5K]

Answer:

E = kQ / r^2 = 2.34*10^21 V/m

where k = 8.99*10^9 m/F

Q = 82 * 1.6*10^-19 C

r = 7.1*10^-15 m

Explanation:

14.2 FM = 2.34×10^21 V/m

6 0
3 years ago
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