Question

Lines a and b are cut by transversal f. At the intersection of lines f and a, the top left angle is 96 degrees. At the intersection of lines b and f, the bottom right angle is (6 x minus 36) degrees. What must be the value of x so that lines a and b are parallel lines cut by transversal f? 10 20 22 32

Answer 1

Answer:

22

Step-by-step explanation:

Answer 2

Answer: 22

Step-by-step explanation:

Lines a and b are cut by transversal f.

Then from the given information,

$6x-36=96$      [ If two parallel lines are cut by a transversal then, the alternate exterior angles are equal. ]

$\Rightarrow\ 6x=96+36\\\\\Rightarrow\ 6x=132\\\\\Rightarrow\ x=\dfrac{132}{6}\\\\\Rightarrow\ x=22$

Hence, the value of x so that lines a and b are parallel lines cut by transversal  = 22