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Mathematics

2 answers:

labwork [276]2 years ago

7 0

Answer:

Explanation:

So in the bag, there are 10 marbles, and 4 of them are blue, so if he drew from the bag 10 times, we can assume the fraction:

4/10

Next, we see that the denominator, or the number times Cade is drawing from the bag is 30, which makes us multiply most sides of the fraction by 3:

12/30

So I would say 12/30, but again, he wouldn't draw a blue exactly 4 times, and it may be more or less, so either 8/12....

Hope this helps!

Allisa [31]2 years ago

3 0

Answer:

C. 12

Step-by-step explanation:

Find the percentage of him drawing a blue marble.

4/10 = 0.4

He has a 40% chance of picking blue.

Find 40% of 30.

He would draw a blue marble around 12 times.

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A prism is completely filled with 3996 cubes that have edge lengths of 13 in. What is the volume of the prism? Enter your answ

ANEK [815]

First, solve for the volume of each cube through the equation,
V = e³
Substituting the known value,
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3 0

3 years ago

Read 2 more answers

I have attached a picture of the question.

sleet_krkn [62]

Its same i think

100-40=60
130-70=60

8 0

2 years ago

When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a 99% confidence interval for

juin [17]

Answer: 0.332 < p < 0.490

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

$\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where n= sample size

$\hat{p}$ = sample proportion

z* = critical z-value.

As per given , we have

n= 258

Sample proportion of college students who own a car = $\hat{p}=\dfrac{106}{258}\approx0.411$

Critical z-value for 99% confidence interval is 2.576. (By z-table)

Therefore , the 99% confidence interval for the true proportion(p) of all college students who own a car will be : $0.411\pm (2.576)\sqrt{\dfrac{0.411(1-0.411)}{258}}\\\\=0.411\pm (2.576)\sqrt{0.00093829}\\\\= 0.411\pm (2.576)(0.0306315197142)\\\\=0.411\pm 0.0789=(0.411-0.0789,\ 0.411+0.0789)\\\\=(0.3321,\ 0.4899)\approx(0.332,\ 0.490)$