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sweet [91]
3 years ago
11

Darrin has 702 CDs in his collection Dana has 367 CDs and her collection how many more CDs does Darrin have more than dana

Mathematics
1 answer:
sp2606 [1]3 years ago
4 0
Darrin got 335 more cds. 702-367=335
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The temperature of the water in Emily's fish tank was 78 on Sunday the water temperature changed by -3 on Monday and then 3 on T
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Answer:

change was 0

temp on tuesday was 78

Step-by-step explanation:

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Write 2x+5/x + 3/x+3 as a single fraction to it's simplest form​
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John is trying to estimate how tall a tree is. the shadow created by the tree is 18 feet long. john is 6 feet tall, and his shad
Alecsey [184]
Make a comparison
\frac{height}{shadow}= \frac{height}{shadow}
\frac{heightof tree}{shadow of three}= \frac{heightofJohn}{shadow of John}

Plug the numbers into the equation above
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\frac{heightof tree}{shadow of three}= \frac{heightofJohn}{shadow of John}
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Do cross multiplication
3.5h = 6 × 18
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to the nearest hundredth
h = 30.86 feet
to the nearest tenth
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3 0
4 years ago
Ryder shot a model rocket over an area that consists of two grassy areas, shown in green, and an area with no grass, shown in wh
kolezko [41]

The rocket has a 2/3 chance of landing in the grassy area, 2 out of 3 areas in the total area are grassy. Cross multiply to turn 2/3 into a percentage, and you get 66%. You can also divide 2 by 3 to get a 0.66 chance. Presuming that 0.2, 0.3, 0.4, and 0.6 are your answer options for this equation, i would say 0.6. If not then the answer is 0.66, 66%, or 2/3 chance

7 0
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Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0
BartSMP [9]

The power series for given function g(x)=\frac{4x}{(x-1)(x+3)} is g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}

We can write g(x) as,

\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\

We know that, \frac{1}{1-x}=\sum{_{n=0}^\infty}~{x^n} if |x| < 1

and \frac{1}{1-(-\frac{x}{3} )}=\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n  if |\frac{x}{6}| < 1

\Rightarrow g(x)=-\sum{_{n=0}^\infty}~x^n+\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n\\     if |x| < 1 and  if |\frac{x}{6}| < 1

\Rightarrow g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n) if |x| < 1

Therefore, the power series for given function g(x)=\frac{4x}{(x-1)(x+3)} is g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)

Learn more about the power series here:

brainly.com/question/11606956

#SPJ4

5 0
2 years ago
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