All categories

3 years ago

Put 2/3 5/7 16/21 in order from least to greatest

Mathematics

2 answers:

hodyreva [135]3 years ago

5 0

Answer:

5/7, 2/3, and 16/21

Step-by-step explanation:

If you put them all under the same denominator you will get 2/3=14/21, 5/7= 10/21, and 16/21. And if you put them in order it is 10/21, 14/21, and 16/21. Hope this helps, let me know if correct!!

Shkiper50 [21]3 years ago

5 0

2/3, 5/7, 16/21

Step-by-step explanation:

turn them into decimals

You might be interested in

What is the Axis of Symmetry?

Ann [662]

the axis of symmetry would be x=1

8 0

3 years ago

Help me PLEASEEEEEEEEEEEEE

qwelly [4]

Answer:

D. 144

Step-by-step explanation:

find the volume of the shipping container and divide it by the volume of a box.

$2\frac{2}{3}$ × $1$ × $2$ = $\frac{16}{3}$

$\frac{1}{3}$ × $\frac{1}{3}$ × $\frac{1}{3}$ = $\frac{1}{27}$

$\frac{16}{3}$ divided by $\frac{1}{27}$ is 144.

4 0

2 years ago

PLEASE HELP ASAP<br> could i just count the squares to get the right answer

natulia [17]

Answer:

a)20 is the answers for the question

Step-by-step explanation:

please give me brainlest and follow me

6 0

2 years ago

Which graph represents y as a function of x?

Lorico [155]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Tesla Battery Recharge Time.The electric vehicle manufacturing company Tesla estimates that a driver who commutes 50 miles per

madam [21]

Answer:

a.) f(x) = $\frac{1}{30}$ where 90 < x < 120

b.) $\frac{2}{3}$

c.) $\frac{2}{3}$

d.) $\frac{1}{2}$

Step-by-step explanation:

Let

X be a uniform random variable that denotes the actual charging time of battery.

Given that, the actual recharging time required is uniformly distributed between 90 and 120 minutes.

⇒X ≈ ∪ ( 90, 120 )

a.)

Probability density function , f (x) = $\frac{1}{120 - 90} = \frac{1}{30}$ where 90 < x < 120

b.)

P(x < 110) = $\int\limits^{110}_{90} {\frac{1}{30} } \, dx$

= $\frac{1}{30}[x]\limits^{110}_{90} = \frac{1}{30} [ 110 - 90 ] = \frac{1}{30} [ 20] = \frac{2}{3}$

c.)

P(x > 100 ) = $\int\limits^{120}_{100} {\frac{1}{30} } \, dx$

= $\frac{1}{30}[x]\limits^{120}_{100} = \frac{1}{30} [ 120 - 100 ] = \frac{1}{30} [ 20] = \frac{2}{3}$

d.)

P(95 < x< 110) = $\int\limits^{110}_{95} {\frac{1}{30} } \, dx$

= $\frac{1}{30}[x]\limits^{110}_{95} = \frac{1}{30} [ 110 - 95 ] = \frac{1}{30} [ 15] = \frac{1}{2}$

7 0

3 years ago