Answer:
46°
Step-by-step explanation:
When secants intersect each other and a circle, the external angle (A) is half the difference of the intercepted arcs:
∠A = (arcDC -arcBC)/2
12° = (arcDC -22°)/2 . . . . . . . fill in the given numbers
24° = arcDC -22° . . . . . . . . . multiply by 2
46° = arcDC . . . . . . . . . . . . . add 22°
Answer: a. 
Step-by-step explanation:
Angles XQL and MQR are congruent because they are vertical angles. So
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
Solve for <em>b</em> :
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
209 - 146 = 13 <em>b</em> - 4<em> b</em>
63 = 9 <em>b</em>
<em>b</em> = 63/9 = 7
Then the measure of angle XQL is
(209 - 13*7)º = 118º
Standard form is
ax+by=c
where a,b,c are integers
y+3=1/4x
timesboth sides by 4
4y+12=x
minus x both sides
-x+4y+12=0
minus 12 both sides
-x+4y=-12
(I like x to be positive so)
times both sides by -1
1x-4y=12
a=1
b=-4
c=12
Add 25 to both sides x-25 +25 =7 +25
x =32
