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Karolina [17]
3 years ago
8

Which table represents a linear function

Mathematics
1 answer:
Sphinxa [80]3 years ago
8 0

Answer:

The bottom right function.

Step-by-step explanation:

The bottom right function is the only function with a common ratio.

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Simplify <br><br>(5i²+8i+10) - (3i²-10i+3)​
Leona [35]

Answer:

2i^2+18i+7

Step-by-step explanation:

(5i^2+8i+10)-(3i^2-10i+3)

5i^2+8i+10-3i^2+10i-3

2i^2+18i+7

4 0
3 years ago
How do you do 111? Explanation pls
IceJOKER [234]

Answer:

B. 2 3/5

Step-by-step explanation:

how i would solve this expression is start out by converting "4 1/3" into an improper fraction.

4 1/3 is equivalent to 13/3

next to find out how much water melissa used we have to multiply 3/5 by our improper fraction giving us this expression:

13/3 x 3/5

solving a fraction is simple, multiply the numerator by numerator,

and denominator by denominator.

so, we will end up with

39/15 or simplified to 2 3/5

hope this helps :D

7 0
3 years ago
Y=3x+1 on a table graph
fgiga [73]

Step-by-step explanation:

Use a Table of Values to Graph the Equation y =3x+1. y=3x+1 y = 3 x + 1. Substitute −2 - 2 for x x and find the result for y y . y=3(−2)+1 y

3 0
3 years ago
How do you graph exponential functions. Please explain because I have like 40 problems and I don't know how to do them so one pr
BaLLatris [955]
Find your y intercep which is your c value then the vortex which you have to do aos and then plug in to find your other point and then graph
8 0
3 years ago
Solve the equation and show all work. 4|x + 1/3| = 20 <br> i'm kind of stuck hhh
34kurt

Absolute value is a function that takes some number and outputs the size of that number, regardless of the sign. By definition, |x|=x if x\ge0, and |x|=-x if x.

For example,

  • |2| = 2 because the input 2 is positive, so the input is unchanged;
  • |-3| = -(-3) = 3 because the input -3 is negative, so the sign is switched.

What this means for this problem is that there are two cases to consider:

  • If x+\frac13\ge0, then \left|x+\frac13\right|=x+\frac13, so that

4\left(x+\dfrac13\right)=20\implies x+\dfrac13=5\implies\boxed{x=\dfrac{14}3}

  • On the other hand, if x+\frac13, then \left|x+\frac13\right|=-\left(x+\frac13\right), so

-4\left(x+\dfrac13\right)=20\implies x+\dfrac13=-5\implies\boxed{x=-\dfrac{16}3}

6 0
4 years ago
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