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2 years ago

Which exponential function models how much a $52,500 car depreciates at 9%

Mathematics

1 answer:

hram777 [196]2 years ago

3 0

Answer:

y = 52500(.91)^x

Step-by-step explanation:

Exponential functions are written y = ab^x where a is the starting point and b is the common ratio. We know the initial worth is 52500 and each year the worth decreases 9% of the original year, making it work 91% of the previous value.

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Alison's car travels at 65 miles per hour. How far does she travel in 4.5 hours?

pantera1 [17]

Answer:

292.5 miles

Step-by-step explanation:

Ok so what you want to do is multiply 4.5 and 65 together.

She travels at 65 miles per hour and she travels for 4.5 hours

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3 years ago

The green family went out for dinner at their favorite restaurant. the cost of their food came to $52.00. they must also pay 6%

riadik2000 [5.3K]

$52 × .06 = 3.12
52 + 3.12 = 55.12
55.12 × 0.15 = 8.27
55.12 + 8.27 = 63.39

7 0

3 years ago

Complete the factorization.

lyudmila [28]

If you would like to complete the factorization, you can do this using the following steps:

<span>4p^2 + 36p + 81 = (2p + 9) * (2p + 9) = (2p + 9)^2
</span>
The correct result would be 9.

6 0

3 years ago

If y=e5t is a solution to the differential equation

a_sh-v [17]

Answer:

k = 30, $y(t) = C_1e^{5t}+C_2e^{6t}$

Step-by-step explanation:

Since $y=e^{5t}$ is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

$\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}$

Then, replacing the derivatives in the equation we have:

$25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0$

Since $e^{5t}$ is a positive function, we have that

$25-55+k = 0 \rightarrow k = 30$ .

Now, consider a general solution $y(t) = Ae^{rt}, A \in \mathbb{R}$ , then, by calculating the derivatives and replacing them in the equation, we get

$Ae^{rt}(r^2-11r+30)=0$

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

$y(t) = C_1e^{5t}+C_2e^{6t}$

8 0

3 years ago

I need this fast yal. i am willing to give brainly

andreyandreev [35.5K]

Answer:

The answer is

y = 6x + 43

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

The original line is y = 6x + 1

Comparing with the general equation above

Slope = 6

Since the lines are parallel their slope are also the same

Slope of parallel line = 6

The equation of the line using point (-7,1) and slope 6 is

We have the final answer as

y = 6x + 43

Step-by-step explanation:

srry if this is wring, its what i got also pls give brainliest, im trying to get to vituoso :3

7 0

3 years ago