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3 years ago

Solve the equation below for x. 5x- 2 = -7 What is x=_____

Mathematics

1 answer:

Sati [7]3 years ago

6 0

Answer:

x = -1

Step-by-step explanation:

Start with adding 2 to -7

-7 + 2

=-5

Then divide by 5

-5/5

=-1

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Are you able to write?

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Answer:

Well isn't anyone able to write?

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3 years ago

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In 3-4 sentences, describe how you would find a line parallel to the line 2x + 5y = 15 that goes through the point (-10, 1). Be

larisa86 [58]

the parallel line is 2x+5y+15=0.

Step-by-step explanation:

ok I hope it will work

soo,

Solution

given,

given parallel line 2x+5y=15

which goes through the point (-10,1)

now,

let 2x+5y=15 be equation no.1

then the line which is parallel to the equation 1st

2 x+5y+k = 0 let it be equation no.2

now the equation no.2 passes through the point (-10,1)

or, 2x+5y+k =0

or, 2*-10+5*1+k= 0

or, -20+5+k= 0

or, -15+k= 0

or, k= 15

putting the value of k in equation no.2 we get,

or, 2x+5y+k=0

or, 2x+5y+15=0

which is a required line.

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1 year ago

What is -8 • 7 + 33 / -11

Strike441 [17]

-8 x 7 = -56

33/-11 = -3

-56

-03

_______

-59

-59 is your answer!

Hope I helped!

Good Luck!

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3 years ago

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Un ganadero está reparando una mezcla de avena y harina de maíz para ganado. Cada onza de avena proporciona 4 gramos de proteína

Feliz [49]

Answer:i love you

Step-by-step explanation:

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3 years ago

If x, y, and z are integers greater than 1, and (327)(510)(z) = (58)(914)(xy), then what is the value of x? (1) y is prime (2) x

Virty [35]

Answer:

1) 5

2) 5

Step-by-step explanation:

Data provided in the question:

(3²⁷)(5¹⁰)(z) = (5⁸)(9¹⁴)( $x^y$ )

Now,

on simplifying the above equation

⇒ (3²⁷)(5¹⁰)(z) = (5⁸)((3²)¹⁴)( $x^y$ )

⇒ (3²⁷)(5¹⁰)(z) = (5⁸)(3²⁸)( $x^y$ )

⇒ $(\frac{3^{27}}{3^{28}})(\frac{5^{10}}{5^8})z=x^y$

⇒ $(\frac{5^2}{3})z=x^y$

⇒ $\frac{5^2}{3}=\frac{x^y}{z}$

we can say

x = 5, y = 2 and, z = 3

Now,

(1) y is prime

since, 2 is a prime number,

we can have

x = 5

2) x is prime

since 5 is also a prime number

therefore,

x = 5

8 0

3 years ago