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2 years ago

5/ 2 x ≤ -14 A. -10.3 B. -6 C. -5.6 D. -5

Mathematics

2 answers:

Advocard [28]2 years ago

4 0

Answer:

Step-by-step explanation:

5/2x<_-14

5x<_-28

5x/5<_-28/6

X<_-5.6

Inessa05 [86]2 years ago

4 0

C. It’s the only logical answer that I would think is right

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Voltage sags and swells. The power quality of a transformer is measured by the quality of the voltage. Two causes of poor power

zysi [14]

Answer:

$z-score = 1.57$

$z-score_s = -3.36$

Step-by-step explanation:

From the question we are told that

The sample size is n = 103

The sample mean of sag is $\= x_1 = 353$

The sample mean of swells is $\= x_2 = 184$

The standard deviation of sag is $s_1 = 30$

The standard deviation of swells is $s_2 = 25$

The number of swell for a randomly selected transformer is k = 100

The number of sag for a randomly selected transformer is c = 400

Generally the z-score for the number of swells is mathematically represented as

$z-score_s = \frac{ k - \= x_2}{s_2}$

=> $z-score_s = \frac{ 100- 184}{25}$

=> $z-score_s = -3.36$

Generally the z-score for the number of sags is mathematically represented as

$z-score = \frac{ c - \= x_1}{s_1}$

$z-score = \frac{ 400 - 353}{30}$

$z-score = 1.57$

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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There are 450 computer's in a technology store. Alex Bought 231 of them for school. Each one was $230. He has $10,000. How much

stepan [7]

231 x 230 = 53,130
mans in negatives

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2 years ago

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2 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

2 years ago