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SVEN [57.7K]
3 years ago
7

Simplify the expression: 62^7 +1 + 6xy + 8z^7 + 9 + 6yx I WILL GIVE BRAINLIEST.

Mathematics
1 answer:
OLga [1]3 years ago
4 0
Answer: 62^7+10+12xy+8z^7
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For example, if your fraction was 1 1/2, you would graph it on the x axis halfway between 1 and 2
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4 years ago
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I need help with this fast! Thanks!
zavuch27 [327]

Answer: 8 1/20 or 8.05.

Step-by-step explanation: First you would want to make 9 3/4 - 2 1/5 to 39/4 - 11/5. We need to get the LCD or Least Common denominator of 4 and 5, which is 20. The rule is what you multiplied the denominator by you must multiply the numerator by, so our new equation is 195/20 - 44/20, which is 151/20. Now, we have to find the LCD of 2 and 20, which is 10. So 151/20 + 10/20 is 161/20 or 8 1/20.

4 0
3 years ago
What is the approximate surface area of the figure?
vampirchik [111]

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5 0
3 years ago
given the equations 9x + (3)/(4)y + 6 and 2x + (1)/(2)y=9 by what factor would you multiply the sencond equation to eliminate y
Paul [167]

Answer:

  -3/2

Step-by-step explanation:

If the first equation is 9x +3/4y = 6, then the solution would look like this:

  \left(9x+\dfrac{3}{4}y\right)-\dfrac{3}{2}\left(2x+\dfrac{1}{2}y\right)=(6)-\dfrac{3}{2}(9)\\\\6x=-\dfrac{15}{2}\\\\x=-\dfrac{15}{12}=-\dfrac{5}{4}\\\\2\left(-\dfrac{5}{4}\right)+\dfrac{1}{2}y=9\ \longrightarrow\ y=2\left(9+\dfrac{5}{2}\right)=23

An appropriate multiplier is -3/2.

4 0
4 years ago
Help for 1-4 and remember show work
Vanyuwa [196]
1. C) $30.00
If you find how much each Pound is worth, which is $2.50 you multiply that by 12 which is $30.00.
2. < because -3.4 is father from 0 on a number line and -2.1 is closest to 0 on the number line so -2.1 is greater than -3.4. | -3.4 < -2.1
3. C) 1/4 because you need to be able to turn the fraction into a decimal and you need to multiply 4 and 1 by 5 and that is 5/20 then you multiply 5 and 20 by 5 and that gives you 25/100 and now you can turn it into a decimal which is 0.25 and 0.27 is greater than 0.25.
4. A) I because if point S is at (-2, 10) it would be in quadrant II so if point T is a reflection of point S than point T is in the I quadrant because the y-axis is the vertical line going up and down. So you put point T across the y-axis which is
at (2, 10) in quadrant I.

3 0
3 years ago
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