Question

given the equations 9x + (3)/(4)y + 6 and 2x + (1)/(2)y=9 by what factor would you multiply the sencond equation to eliminate y and solve the system through linear combinations

Answer 1

Answer:

  -3/2

Step-by-step explanation:

If the first equation is 9x +3/4y = 6, then the solution would look like this:

  $\left(9x+\dfrac{3}{4}y\right)-\dfrac{3}{2}\left(2x+\dfrac{1}{2}y\right)=(6)-\dfrac{3}{2}(9)\\\\6x=-\dfrac{15}{2}\\\\x=-\dfrac{15}{12}=-\dfrac{5}{4}\\\\2\left(-\dfrac{5}{4}\right)+\dfrac{1}{2}y=9\ \longrightarrow\ y=2\left(9+\dfrac{5}{2}\right)=23$

An appropriate multiplier is -3/2.