Ask question

Ask question

All categories

2 years ago

7

What is the value of x in 6-3x=5x-10x+12

1 answer:

Alexus [3.1K]2 years ago

5 0

3 is the right answer

You might be interested in

find two consecutive intergers who sum is equal to the difference of three times the larger and two times the smaller

vekshin1

Answer:

4 and 6

Step-by-step explanation:

Let integers be x and x+2 Then:-

x + x + 2 = 3(x + 2) - 2x

2x + 2 = 3x + 6 - 2x

2x + 2 = x + 6

x = 4

The numbers are 4 and 6.

3 0

2 years ago

Which is the decimal expansion of 7 Over 22

Fed [463]

Answer: 0.31

Step-by-step explanation:

7/22 is 0.31

6 0

3 years ago

Read 2 more answers

4a + 6b= 10 2a - 4b =12 what does 12a=

mixer [17]

4a + 6b = 10
2a - 4b = 12...multiply by -2
----------------
4a + 6b = 10
-4a + 8b = - 24 (result of multiplying by -2)
------------------add
14b = - 14
b = -14/14
b = -1

2a - 4b = 12
2a - 4(-1) = 12
2a + 4 = 12
2a = 12 - 4
2a = 8
a = 8/2
a = 4

so 12a = 12(4) = 48 <==

3 0

3 years ago

What is the sum or whatever of this equation. This equation is V = πx3^2x8

navik [9.2K]

Answer:

$V=226.08$

Step-by-step explanation:

To evaluate $V$ from the following expression:

$V=\pi\times3^2\times 8$

Taking $\pi=3.14$

$V=3.14\times 3^2\times 8$

$V=3.14\times 9\times 8$

∴ $V=226.08$

6 0

2 years ago

a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s

slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So, $w = k V$ , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h distance, pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is, $V= \frac{1}{3} *A* 5$

So, weight of original pyramid, $W = k *(\frac{1}{3} *A* 5) = 800$

Volume of small pyramid is, $v = \frac{1}{3}* a* h$

So, weight of small pyramid, $w = k*(\frac{1}{3}* a* h)=400$

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So, $\frac{a}{A} = (\frac{h}{5}) ^{2}$

$a = (\frac{h}{5} )^{2}A$

Substituting value of a in equation $k*(\frac{1}{3}* a* h)=400$

So, $k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400$

$(k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400$

Since, $(k *\frac{1}{3} *A* 5) = 800$ , substitute in above equation.

So, $800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet$

Learn more:

brainly.com/question/17950304

6 0

2 years ago

Read 2 more answers