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Ronch [10]
3 years ago
10

Find the amount of the discount on a $234 item with a 15% discount

Mathematics
2 answers:
stepan [7]3 years ago
8 0

Answer:

$35.10

Step-by-step explanation:

hodyreva [135]3 years ago
3 0
I believe it's
234-15%= 198.9
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The ratio of white marbles to black marbles in a jar is 4:9.
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For every 4 white marables there are 9 black marables in the jar
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Factor x^5+4x^4−7x^3−34x^2−24x
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This is your perfect answer

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A group of fitness club members lose a combined total of 28 kilograms in 1 week. There are approximately 2.2 pounds in 1 kilogra
lesya [120]

Answer:

8.8

Step-by-step explanation:

first you divide 28/7 (because there are 7 days in the week) you take that number, which is 4 and multiply it was 2.2 to convert the 4 kilograms into pounds.

3 0
3 years ago
2/3y + v = s solve for y
DanielleElmas [232]

Answer:

y = \frac{3s-3v}{2}

Step-by-step explanation:

Given

\frac{2}{3} y + v = s ( subtract v from both sides )

\frac{2}{3} y = s - v

Multiply through by 3 to clear the fraction

2y = 3s - 3v ( divide both sides by 2 )

y = \frac{3s-3v}{2}

3 0
4 years ago
From a shipment of 65 transistors, 6 of which are defective, a sample of 5 transistors is selected at random.
Vladimir79 [104]

Answer:

a) 8259888

b) 34220

c) 45057474

Step-by-step explanation:

Given,

The total number of transistor = 65,

In which, the defective transistor = 6,

So, the number of non defective transistor = 65 - 6 = 59,

Since, out of these transistor 5 are selected,

a) Thus, the number of ways = the total possible combination of 5 transistors = {65}C_ 5

=\frac{65!}{(65-5)!5!}

=8259888

b) The number of samples that contains exactly 3 defective transistors = the possible combination of exactly 3 defective transistors = {6}C_3\times {59}C_2

=\frac{6!}{(6-3)!3!}\times \frac{59!}{(59-2)!\times 2!}

=20\times 1711

=34220

c) The number of sample without any defective transistor = The possible combination of 0 defective transistor = ^6C_0\times ^{59}C_5

=1\times 45057474

=45057474

5 0
3 years ago
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