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lyudmila [28]
2 years ago
8

6(X - 2) = -48 Find x

Mathematics
2 answers:
Alex787 [66]2 years ago
5 0
6(X - 2) = -48

6X - 12 = -48

6X = -48 + 12

6X = -36

6X/6 = -36/6

X = -6
Darya [45]2 years ago
3 0

Answer:

6x-12=-48

6x=-36

x=-6

Step-by-step explanation:

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Peepeepoopooo I need help please
Irina18 [472]

Answer:

16.9

Step-by-step explanation:

We can use a proportion also in this case

51.6 : 23 = 38 : NO

NO = (38 x 23)/51.6 = 16.9

6 0
2 years ago
If F(X)= 6X-4 and F(A)= 26 what is the value of a? Explain
sammy [17]
Easy if you know the formula

all this means is that your x value is a, and when it is, will give you the value 26.

f(a) = 6a - 4 = 26

6a = 30
a = 5
3 0
2 years ago
Read 2 more answers
1) g=-y+c/x, solve for X
Sindrei [870]

Answer:

the solution  x = \frac{c}{g-y}

Step-by-step explanation:

<u>Step 1:-</u>

Given problem g=\frac{-y+c}{x}

here l.cm is x

g = \frac{x y+c}{x}

cross multiplication we get ,

g x = x y +c

<u>Step 2</u>:-

subtracting x y on both sides , we get

g x - x y = c

taking common 'x' we get,

x(g-y) = c

<u>Final answer</u>:-

x = \frac{c}{g-y}

3 0
3 years ago
ASAP. Look at the picture. Answer choices are: A) the spring has no stretch when a force of 1 pound is applied. B) the spring st
Katyanochek1 [597]

Answer:

D) the spring has a length of 1 inch when no force is applied

3 0
3 years ago
slader (a) Find parametric equations for the line through (4, 1, 8) that is perpendicular to the plane x − y + 4z = 2. (Use the
Pavel [41]

Answer:

(x(t), y(t), z(t)) = (4 + t, 1 - t, 8 + 4t)

xy - plane    (x, y, z) = (2, -1, 0)

yz - plane    (x, y, z) = (0, 5, -8)

xz - plane     (x, y, z) = (5, 0, 12)

Step-by-step explanation:

The given point (x, y ,z) = (4, 1, 8)

The plane x -y + 4z = 2

Normal vector (n) = < 1, -1, 4 >

The equation of line through point (4, 1, 8) and the plane is:

(x(t), y(t), z(t)) = (4, 1, 8) + t(1, -1, 4)

(x(t), y(t), z(t)) = (4 + t, 1 - t, 8 + 4t)

Any point on the line P(x, y, z) = ( 4 + t, 1 - t, 8 + 4t)

xy-Pane ⇒ z = 0

8 + 4t = 0

4t = - 8

t = -8/4

t = -2

∴

(x, y, z) = (4 - 2, 1 - 2, 8 + 4(-2))

(x, y, z) = (2, -1, 0)

yz-plane ⇒ x = 0

4 + t = 0

t = -4

∴

(x, y, z) = (4 + (-4) , 1-(-4), 8 + 4(-4)

(x, y, z) = (0, 5, -8)

xz-plane ⇒ y = 0

1 - t = 0

-t = -1

t = 1

∴

(x, y, z) = ( 4 + 1, 1 - 1, 8 + 4(1) )

(x, y, z) = (5, 0, 12)

6 0
3 years ago
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