Is the equation y + 1=7(x+2) in point slope form

denis-greek [22]

Yes.

It’s a flat figure (2D), and all of its lines are connected with one another. There aren’t any open points/lines. It’s closed to create a shape. This means it’s a polygon.

3 0

2 years ago

I NEED HELP ASAP, THAK YOU IN ADVANCED

german

1. If Sheryl works 6.5 hours in a day, she makes approximately 85 currency.

2A. If Sherly had not worked for a single hour, she would get no money.

If she worked for 1 hour, here wage would approximately be equal to 13 currency.

If Sheryl works 9 hours she will make approximately 117 currency.

Step-by-step explanation:

Step 1:

To calculate how much Sheryl makes if she works 6.5 hours a day, we check the graph to see what the y value of the graph is when $x =6.5$ .

When $x =6.5$ , the line falls on $y = 85.$

So if Sheryl works 6.5 hours in a day, she makes approximately 85 currency.

Step 2:

The two points on the graph are at (0, 0) and (1, 13).

This means that if Sherly had not worked for a single hour, she would get no money.

If she worked for 1 hour, here wage would approximately be equal to 13 currency.

These two statements explain the two points on the graph.

Step 3:

To calculate how much Sheryl makes if she works 9 hours, we must create an equation that represents how much money she makes.

If she earns approximately 13 currency an hour, her wage is $y = 13x$ , where x is the number of hours worked and y is the wage.

When $x =9$ , $y = 9(13) = 117.$

So if Sheryl works 9 hours she will make approximately 117 currency.

5 0

4 years ago

Please help me, A candle is in the shape of a frustum (a cone with the top cut off). Calculate the volume of the candle to the n

MariettaO [177]

Answer:

Height = 8 cm

You will need this formula (see attached):

Volume = [PI * 8 * (2² + 2*4 + 4²)] / 3

Volume = [3.14159265 * 8 * (4 + 8 + 16)] / 3

Volume = 234.57 cubic centimeters

Source: http://www.1728.org/volcone.htm

Step-by-step explanation:

3 0

2 years ago

what is the answer to Graph the function. f(x)=cos(x)−3 Use 3.14 for π i need it now im struggling on this test

kvv77 [185]

Answer:

we can draw the graph of cosine with amplitude 2.

Step-by-step explanation:

In the given function g(x) = 2cosx we know the following parameters which are helpful to draw the graph.

Its a cosine graph given in the form of y = acos(Bx + c) + d

Here a is amplitude, period = , c = phase shift, d = vertical shift

We know a = 2, B = , c = 0, d = 0.

8 0

3 years ago

Suppose two dice are tossed and the numbers on the upper faces are observed. Let S denote the set of all possible pairs that can

Thepotemich [5.8K]

Answer:

▪A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)}

▪C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B bar = {(1,2) (1,4) (1,6) (3,2) (3,4) (3,6) (5,2) (5,4) (5,6)}

▪A bar∪B = {(1,1) (1,3) (1,5) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,3) (3,5) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,3) (5,5) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}

▪A bar∩C = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)}

Step-by-step explanation:

S = {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)}

A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)} (second die is even)

B = {(1,1) (1,3) (1,5) (2,2) (2,4) (2,6) (3,1) (3,3) (3,5) (4,2) (4,4) (4,6) (5,1) (5,3) (5,5) (6,2) (6,4) (6,6)} (sum of the two numbers is even)

C = {(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,3) (2,5) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,3) (4,5) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,3) (6,5)} (at least one in the pair is odd i.e one of the pair is odd or both are odd)

A bar = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)} (the pairs that are not in A)

B bar = {(1,2) (1,4) (1,6) (2,1) (2,3) (2,5) (3,2) (3,4) (3,6) (4,1) (4,3) (4,5) (5,2) (5,4) (5,6) (6,1) (6,3) (6,5)} (the pairs that are not in B)

C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)} (the pairs that are not in C)

▪A = {(1,2) (1,4) (1,6) (2,2) (2,4) (2,6) (3,2) (3,4) (3,6) (4,2) (4,4) (4,6) (5,2) (5,4) (5,6) (6,2) (6,4)(6,6)}

▪C bar = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)}

▪A∩B = {(2,2) (2,4) (2,6) (4,2) (4,4) (4,6) (6,2) (6,4) (6,6)} (intersection: the pairs that are common to both A and B)

▪A∩B bar = {(1,2) (1,4) (1,6) (3,2) (3,4) (3,6) (5,2) (5,4) (5,6)} (intersection: the pairs that are common to both A and B bar)

▪A bar∪B = {(1,1) (1,3) (1,5) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,3) (3,5) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,3) (5,5) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)} (union: all the pairs in A bar and B )

▪A bar∩C = {(1,1) (1,3) (1,5) (2,1) (2,3) (2,5) (3,1) (3,3) (3,5) (4,1) (4,3) (4,5) (5,1) (5,3) (5,5) (6,1) (6,3) (6,5)} (intersection: the pairs that are common to both A bar and C)

6 0

3 years ago