Answer:
10 packs of juice and 15 packs of water was bought by Mr. Lincoln
Step-by-step explanation:
Mr. Lincoln buys juice and water for the school picnic. A pack of 8 juice boxes costs $5. A pack of 6 water bottles costs $3. Mr. Lincoln spends $95 for 170 juice boxes and bottles of water.
Solution:
Let x represent the number of packs of juice boxes bought by Mr. Lincoln and let y represent the number of packs of water bottles bought by Mr. Lincoln.
Each pack of juice cost $5 while each pack of water cost $3. Mr. Lincoln spends $95, therefore:
5x + 3y = 95 (1)
Each pack of juice contain 8 juice boxes and each pack of water contain 6 water bottles. Since 170 juice boxes and bottles of water was bought, therefore:
8x + 6y = 170 (2)
Solving equations (1) and (2) simultaneously. Multiply equation (1) by 2 and then subtract equation (2) from the result to get:
2x = 20
x = 10
Substitute x = 10 in equation (1):
5(10) + 3y = 95
50 + 3y = 95
3y = 45
y = 15
Hence 10 packs of juice and 15 packs of water was bought by Mr. Lincoln
Answer:
Vw=6
Step-by-step explanation:
Answer:
200 -20d
(Have a nice day)
Answer:
A variable whose variation does not depend on that of another.
Among all the filled solutions first four solutions, sixth , eight , elventh to thirteenth are correct.
Given twenty expressions and we are required to find the value of expressions when x=0 and x=1.
Expression is combination of numbers, fractions, coefficients, mostly not found in equal to form.
1)2x+3-2+x
when x=0,
=2*0+3-2+0
=1
when x=1,
=2*1+3-2+1
=4
2)4x-5-2x
when x=0,
=4*0-5-2*0
=-5
when x=1,
=4*1-5-2*1
=-3
3)2-3(x+1)+4x
when x=0
=2-3(0+1)+4*0
=-1
when x=1
=2-3(1+1)+4*1
=0
4)4+3x-x-1
when x=0
=4+3*0-0-1
=3
when x=1
=4+3*1-1-1
=5
5)6x-5-6x
when x=0
=6*0-5-6*0
=-5
6) 5(x+1)-x+2
when x=0
=5(0+1)-0+2
=7
when x=1
=5(1+1)-1+2
=11
7) 2x-7+5x-3
when x=0
=2*0-7+5*0-3
=-10
when x=1
=2*1-7+5*1-3
=-3
8) 3+2x-3
when x=0
=3+2*0-3
=0
when x=1
=3+2*1-3
=2
9) 14-2x-5x+2
when x=0
=14-2*0-5*0+2
=16
when x=1
=14-2*1-5*1+2
=9
10) 5-4x(1+3)+7x
when x=0
=5-4*0(1+3)+7*0
=5
when x=1
=5-4*1(1+3)+7*1
=-4
11) 3x+1
when x=0
=3*0+1
=1
when x=1
=3*1+1
=4
12) 2x+5
when x=0
=2*0+5
=5
when x=1
=2*1+5
=7
13)x-3
when x=0
=0-3
=-3
when x=1
=1-3
=-2
14)2x+3
when x=0
=2*0+3
=3
when x=1
=2*1+3
=5
15) 12x-5
when x=0
=12*0-5
=-5
when x=1
=12*1-5
=7
16) 4x+7
when x=0
=4*0+7
=7
when x=1
=4*1+7
=11
17) 6x-5
when x=0
=6*0-5
=-5
when x=1
=6*1-5
=1
18) 2x
when x=0
=2*0
=0
when x=1
=2*1
=2
19) 16-5x
when x=0
=16-5*0
=16
when x=1
=16-5*1
=11
20) 5-9x
when x=0
=5-9*0
=5
when x=1
=5-9*1
=-4
Hence it is found that among all the filled solutions first four solutions, sixth , eight , elventh to thirteenth are correct.
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