1) Jessica charges $8 an hour for babysitting

1 answer:

6 0

A. The independent variable is time, as time is manipulating the value of her salary.

b. The dependent variable is her cost because what she charges for babysitting depends on how long she works.

c. y = 8x
y = how much she charges for this job
8 = the amount she charges per hour
x = number of hours babysat

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Find the length of side a.<br> please help?

GaryK [48]

Answer:

Hello! I believe your answer is a = 3

Step-by-step explanation:

a= $\sqrt{5^{2}-4^{2} }$ = 3

Have a good day! - Zac

8 0

1 year ago

Read 2 more answers

I don’t know how to do this

stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as $x$ approaches the edges. For example,

$g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}$

has two pieces, $2x+5$ and $x^2-10$ , both of which are continuous by themselves on the provided intervals. In order for $g$ to be continuous everywhere, we need to have

$\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)$

By definition of $g$ , we have $g(-3)=2(-3)+5=-1$ , and the limits are

$\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1$

$\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1$

The limits match, so $g$ is continuous.

For the others: Each of the individual pieces of $f,h$ are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.