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3 years ago

Two angles are complementary. Angle 1 has a

Mathematics

1 answer:

Mademuasel [1]3 years ago

6 0

The value is 50x at least that is what I think it is

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There are 60 gum balls in the machine. 9 of the gum balls are green. What percent of the gum balls are green

Olenka [21]

9% or 51% I think probably 9

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3 years ago

How do you multiply

arsen [322]

Answer:

example 7 x 3 means you add 7 3 times

Step-by-step explanation:

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3 years ago

Anyone wanna help me please

Art [367]

Answer:

the answer to this is x=16.1

8 0

3 years ago

Read 2 more answers

Solve this equation pls

Aleksandr-060686 [28]

Answer:

${ \rm{y = \frac{3 \sqrt{x} + 2x}{ {4x}^{2} } }} \\$

• We are gonna use the quotient rule

${ \boxed{ \bf{ \frac{dy}{dx} = \frac{ {\huge{v} } \frac{du}{dx} - { \huge{u}} \frac{dv}{dx} }{ {v}^{2} } }}} \\$

u is (3√x + 2x)
v is 4x²
du/dx is 3/2√x
dv/dx is 8x

• Therefore:

${ \rm{ \frac{dy}{dx} = \frac{(4 {x}^{2})( \frac{3}{2 \sqrt{x} }) - (3 \sqrt{x} + 2x)(8x) }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{(6 {x}^{2})( {x}^{ - \frac{1}{2} } ) - (24 {x}^{ \frac{3}{2} } + 16 {x}^{2} ) }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{ 6 {x}^{ \frac{3}{2} } - {24x}^{ \frac{3}{2} } - {16x}^{2} }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{ - 18 {x}^{ \frac{3}{2} } - 16 {x}^{2} }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = - 2 {x}^{ \frac{3}{2} } (9 + 8 {x}^{ \frac{4}{3} } ) \div 16 {x}^{4} }} \\ \\ { \boxed{ \boxed{ \rm{ \: \: \frac{dy}{dx} = - \frac{8 \sqrt{ {x}^{ \frac{8}{3} }} + 9}{8x {}^{ \frac{8}{3} } } \: \: }}}}$

5 0

2 years ago

Read 2 more answers

An object is launched from a platform.

tankabanditka [31]

Answer:

Step-by-step explanation:

Ground level is where h = 0, so solve the equation ...

h(x) = 0

-5(x -4)^2 +180 = 0 . . . . substitute for h(x)

(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36

x -4 = 6 . . . . . . . . . . . . . . positive square root*

x = 10 . . . . . . add 4

The object will hit the ground 10 seconds after launch.

_____

* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.

8 0

2 years ago