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Andre45 [30]
3 years ago
5

Two angles are complementary. Angle 1 has a

Mathematics
1 answer:
Mademuasel [1]3 years ago
6 0
The value is 50x at least that is what I think it is
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Step-by-step explanation:

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Answer:

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8 0
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Solve this equation pls
Aleksandr-060686 [28]

Answer:

{ \rm{y =  \frac{3 \sqrt{x}  + 2x}{ {4x}^{2} } }} \\

• We are gonna use the quotient rule

{ \boxed{ \bf{ \frac{dy}{dx} =  \frac{ {\huge{v} } \frac{du}{dx}   - { \huge{u}} \frac{dv}{dx} }{ {v}^{2} }  }}} \\

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• Therefore:

{ \rm{ \frac{dy}{dx} =  \frac{(4 {x}^{2})( \frac{3}{2 \sqrt{x} }) - (3 \sqrt{x} + 2x)(8x)   }{16 {x}^{4} }  }} \\  \\ { \rm{ \frac{dy}{dx}  =  \frac{(6 {x}^{2})( {x}^{ -  \frac{1}{2} }  ) - (24 {x}^{ \frac{3}{2}  } + 16 {x}^{2} ) }{16 {x}^{4} }  }} \\  \\ { \rm{ \frac{dy}{dx}  =  \frac{ 6 {x}^{ \frac{3}{2} }  -  {24x}^{ \frac{3}{2} }  -  {16x}^{2} }{16 {x}^{4} } }} \\  \\ { \rm{ \frac{dy}{dx}  =  \frac{ - 18 {x}^{ \frac{3}{2}  } - 16 {x}^{2}  }{16 {x}^{4} } }} \\  \\ { \rm{ \frac{dy}{dx}  =  - 2 {x}^{ \frac{3}{2} } (9 + 8 {x}^{ \frac{4}{3} } ) \div 16 {x}^{4} }} \\  \\ { \boxed{ \boxed{ \rm{ \:  \:  \frac{dy}{dx}  =   - \frac{8 \sqrt{ {x}^{ \frac{8}{3} }}  + 9}{8x {}^{ \frac{8}{3} } }  \:  \: }}}}

5 0
2 years ago
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An object is launched from a platform.
tankabanditka [31]

Answer:

  10

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Ground level is where h = 0, so solve the equation ...

  h(x) = 0

  -5(x -4)^2 +180 = 0 . . . . substitute for h(x)

  (x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36

  x -4 = 6 . . . . . . . . . . . . . . positive square root*

  x = 10 . . . . . . add 4

The object will hit the ground 10 seconds after launch.

_____

* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.

8 0
2 years ago
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