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mariarad [96]
3 years ago
14

A​ 150-pound person uses 5.1 calories per minute when walking at a speed of 4 mph. How long must a person walk at this speed to

use at least 230 ​calories?
Mathematics
1 answer:
Igoryamba3 years ago
7 0

Answer: 45.1 minutes

Step-by-step explanation:

From the question, we are informed that a 150-pound person uses 5.1 calories per minute when walking at a speed of 4 mph. The number of.

minutes that the person must walk at this speed to use at least 230 ​calories will be:

Let the number of minutes to walk be represented by x

(5.1 × x) = 230

5.1x = 230

x = 230 / 5.1

= 45.1 minutes

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Vaselesa [24]

How to solve your problem

6 0
2 years ago
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Bob has two weekend jobs last weekend he made a total of $77 after working as a cashier for 5 hours and delivering newspapers fo
OlgaM077 [116]

Answer: $9 per hour at his job as a cashier and $8 per hour at his job delivering newspapers.

Step-by-step explanation:

1. Let's call the amount he got paid per hour at his job as a cashier: x.

Let's call the amount he got paid per hour at his job delivering newspapers: y.

2. Keeping on mind the information given in the problem above, you can make the following system of equations:

\left \{ {{5x+4y=77 \atop {6x+3y=78}} \right.

3. You can solve it by applying the Substitution method, as following:

- Solve for one of the variables from one of the equations and substitute it into the other equation to solve for the other variable and calculate its value.

- Substitute the value obtained into one of the original equations to solve for the other variable and calculate its value.

 4. Therefore, you have:

5x+4y=77\\5x=77-4y\\x=\frac{77-4y}{5}=15.4-0.8y

Then:

6(15.4-0.8y)+3y=78\\92.4-4.8y+3=78\\-1.8y=-14.4\\y=8

Finally:

5x+4(8)=77\\5x+32=77\\5x=45\\x=9

Therefore he got paid $9 per hour at his job as a cashier and $8 per hour at his job delivering newspapers.

5 0
3 years ago
Find the value of y for which the lines are parallel<br><br> a-68<br> b49<br> c55<br> d100
dexar [7]
B. 

You know that the angle formed by 51 and y + 6 is equal to 106 because it needs to be supplementary with the 74. Thus, after subtracting you can get 49.
7 0
3 years ago
I understand the equation, it's just not working out. Can anyone help me figure it out? Thanks in advance.
andreyandreev [35.5K]
You put the 15x + 100 on the angle CEB instead of CED. If you put it in the right spot, it should work out fine since they are vertical angles.
4 0
3 years ago
If two right triangles each have a 30° angle, then the
Scorpion4ik [409]

Answer:

b. Similar

Step-by-step explanation:

Although angles are congruent the triangles are not as sides need to be the same too.  Both shapes have 90 degree and 30 degree and add up to 180 degree in each triangle. Therefore each shapes angles are congruent but we dont know there size or scale, so they are similar. if they are the same (shape and size)- in other words, if the lengths of the sides and the angles are the same. So they are similar.

Because the angles are congruent and sizes are not shown they must be similar.

They cannot be obtuse as no angle is larger than 90 degrees and to be obtuse it would have to be larger than 90 deg and lower than 180 deg.

They cannot be equilateral as that means it couldn't be 30 degree and a right angle as equilateral means same angle sizes within 'one' triangle or for every or each triangle; as we know all triangles that are equilateral are 60, 60, 60 degrees to add up to 180 degree and cannot be an equilateral for this reason too as we have right angle triangles and equilateral are not right angles due to being 60 degree angle measures.

They are not fully congruent as we do not know there side measures so they have to be similar.

4 0
3 years ago
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