Y=4x+12
y=-2(x+2)2+2=>y=-4x-4+2=-4x-2=>
y=-4x+2
Use the elimination property:
2y=14
y=7
Put y value back to the first equation: 7=4x+12, solve for x and -5=4xso x=-5/4
(-5/4,7)
You can change the denominator to 10 which will get you to 55/10 + 4/10. You can add these two together to get 59/10
<span>Assuming the reaction is of 1st order, we can
start using the formula for rate of 1st order reaction:</span>
dN / dt = k * N
Rearranging,
dN / N = k dt
Where N = amount of sample, k = rate constant, t = time
Integrating the equation from N = Ni to Nf and t = ti to
tf will result in:
ln (Nf / Ni) = k (tf – ti)
Since k is constant, we can equate to situations.
Situation 1 is triple in size every days, situation 2 is after 20 days.
ln (Nf / Ni) / (tf – ti) = k
ln (3Ni / Ni) / 4 = ln (Nf / 40) / 20
Calculating for Nf,
<span>Nf =
9,720 bacteria </span>
Answer:
1 xx
Step-by-step explanation:
each box got to to worth 1 point representing the x variable so i added 1 plus 1xx and minus 2 to get 1xx
Answer:
the answer is y, I just took the test