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Oksi-84 [34.3K]
3 years ago
11

Rewrite decimal as a fraction 7\9

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
7 0
Hi there!

7/9 is equal to 0.77777 (repeating over and over again)
This fraction cannot be simplified any lower than what it is.
But yes, the decimal number of this is 0.77778 (rounded off this answer would be 0.7778.)

Hope this helps!
ad-work [718]3 years ago
5 0
7/9 is .77 repeating
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Directions: Calculate the area of a circle using 3.14x the radius
Leokris [45]

\qquad\qquad\huge\underline{{\sf Answer}}♨

As we know ~

Area of the circle is :

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

And radius (r) = diameter (d) ÷ 2

[ radius of the circle = half the measure of diameter ]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

<h3>Problem 1</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 4.4\div 2

\qquad \sf  \dashrightarrow \:r = 2.2 \: mm

Now find the Area ~

\qquad \sf  \dashrightarrow \: \pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  {(2.2)}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  {4.84}^{}

\qquad \sf  \dashrightarrow \:area  \approx 15.2 \:  \: mm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 2</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 3.7 \div 2

\qquad \sf  \dashrightarrow \:r = 1.85 \:  \: cm

Bow, calculate the Area ~

\qquad \sf  \dashrightarrow \: \pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (1.85) {}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times 3.4225 {}^{}

\qquad \sf  \dashrightarrow \:area  \approx 10.75 \:  \: cm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>Problem 3 </h3>

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (8.3) {}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times 68.89

\qquad \sf  \dashrightarrow \:area \approx216.31 \:  \: cm {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>Problem 4</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 5.8 \div 2

\qquad \sf  \dashrightarrow \:r = 2.9 \:  \: yd

now, let's calculate area ~

\qquad \sf  \dashrightarrow \:3.14 \times  {(2.9)}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  8.41

\qquad \sf  \dashrightarrow \:area  \approx26.41 \:  \: yd {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 5</h3>

\qquad \sf  \dashrightarrow \:r = d \div 2

\qquad \sf  \dashrightarrow \:r = 1 \div 2

\qquad \sf  \dashrightarrow \:r = 0.5 \:  \: yd

Now, let's calculate area ~

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times (0.5) {}^{2}

\qquad \sf  \dashrightarrow \:3.14  \times 0.25

\qquad \sf  \dashrightarrow \:area \approx0.785 \:  \: yd {}^{2}

・ .━━━━━━━†━━━━━━━━━.・

<h3>problem 6</h3>

\qquad \sf  \dashrightarrow \:\pi {r}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times  {(8)}^{2}

\qquad \sf  \dashrightarrow \:3.14 \times 64

\qquad \sf  \dashrightarrow \:area = 200.96 \:  \: yd {}^{2}

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

8 0
2 years ago
What is the answer to -3k-(-8)+2
NISA [10]

Answer:

-3k + 10

Step-by-step explanation:

-3k - (-8) + 2

-3k + 8 + 2 !!

-3k + 10 → simplified version of the given expression

!! → We got rid of the parenthesis by combining the two negative signs. The rules state that any 2 identical signs combined (in this case, - and -) equal a positive sign (+).

Hope it helped,

BiologiaMagister

6 0
2 years ago
Read 2 more answers
a digital camera costs $ 140 and the sales tax rate is 7.5 % what us tge total cost of the camera after tax round to the nearest
stiv31 [10]
$140(.075) = 10.5
10.5+140= 150.50
the total would be $150.50
5 0
3 years ago
the Indian Ocean is 2/10 of the area of the world's oceans. what fraction represents the area of the remaining oceans that make
Shtirlitz [24]
8/10 or 4/5 is what makes up the remaining oceans
4 0
2 years ago
Please help it’s very urgent and I need the right answer
8090 [49]

Answer:

3x + 15 = 3*10 + 15 = 30 + 15 = 45

<u>3x + 15 = 45</u>

Now,

2x + 25 = 2*10 + 25 = 20 + 25 = 45

<u>2x + 25 = 45</u>

Step-by-step explanation:

3x + 15 + 2x + 25 = 90

or, 5x + 40 = 90

or, 5x = 90 - 40

so, 5x = 50

so, x = 50/5 = 10

3 0
2 years ago
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