Answer:
The Chi-square test of independence
Step-by-step explanation:
The answer to this question is the Chi-square test of independence because it is what is used to determine the existence of an association between nominal/categorical variables. This test is non parametric in nature and it can also be called the chi square test of association.
The data is tabulated. each row is a representation of the category for one of the variables and each column is for the other variable.
Answer:
{ln 4, (2 + 2e^ln 4 − 4 ln 4)} or (1.39, 4.45)
Step-by-step explanation:
From this equation 4x − y = 3
-y = 3 - 4x
then, y = 4x - 3
From line equation y = mx + b
Therefore, the slope is 4
Since the are parallel line, they will have same slope
Finding the derivative of y = 2 + 2e^x − 4x
y = 2 + 2e^x − 4x
y' = 0 + 2e^x - 4
Therefore,
4 = 2e^x - 4
4 = e^x
x = ln 4 = 1.39
To find the y coordinate
y = 2 + 2e^x − 4x
y = 2 + 2e^ln 4 − 4 ln 4
y = 4.45
Hence, they are parallel at point (1.39 and 4.45)
Since they are similar, the dimensions are in the same ratio. L1 = 5, L2 = 15, so they are in a 3:1 ratio. So if V1 = 60, then W1×H1 = 60/5 = 12
W2 must also be 3×W1 and H2 3×H1, and
3×3 = 9. So take 12×9 (W×H1×9) ×15 (L2) = V2
V2 = 12×9×15 = 1620 cm^3
Let me know the right answer when you find out!
A tell me out of 9 13 23
What is the smallest number or the number closest to 0
