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d1i1m1o1n [39]
3 years ago
13

To the nearest degree, what is the measure of each exterior angle of a regular 11-gon?

Mathematics
2 answers:
Licemer1 [7]3 years ago
8 0
<h2>Answer:</h2>

The measure of each exterior angle of a regular 11-gon to the nearest degree is:

                                      33°

<h2>Step-by-step explanation:</h2>

<em>A regular n-gon is a polygon whose measure of all the sides and all the angles are equal i.e. it is a equilateral and equiangular polygon.</em>

We know that the measure of each exterior angle of a regular n-gon is given by:

                           \dfrac{360\degree}{n}

We have:

n=11

Hence, the measure of each exterior angle is given by:

                                      \dfrac{360}{11}\\\\\\=32.7272

Hence, to the nearest degree the measure of the exterior angle is: 33°

Alex73 [517]3 years ago
7 0
Answer: 33°

Explanation:

360 ÷ 11 = 33 (nearest degree)


The Wise Orange knows that exterior angles always sum up to 360°
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Serhud [2]

Answer:

1.) (11,  -7/3),   2.) No solution.  3.)  (1, 3)

Step-by-step explanation:

1.)

2x + 3y = 15

x - 3y = 18

Solve...use elimination method

2x + x + 3y - 3y = 15 + 18

3x = 33

x =11

11 - 3y = 18

-3y = 7

y = -7/3

(11,  -7/3)

---------------------------------------

2.) y = 4x + 4

y = 4x - 4

Use substitution.

4x + 4 = 4x - 4

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3.) y = 5- 2x

4x + 3y = 13

Can use elimination method

2y = 10 - 4x

add it to 4x + 3y = 13

10 + 3y = 2y + 13

y = 3

3 = 5 - 2x

x = 1

(1, 3)

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Step-by-step explanation:

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Step-by-step explanation:

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