To the nearest degree, what is the measure of each exterior angle of a regular 11-gon?

Mathematics

2 answers:

Licemer1 [7]3 years ago

8 0

<h2>Answer:</h2>

The measure of each exterior angle of a regular 11-gon to the nearest degree is:

33°

<h2>Step-by-step explanation:</h2>

<em>A regular n-gon is a polygon whose measure of all the sides and all the angles are equal i.e. it is a equilateral and equiangular polygon.</em>

We know that the measure of each exterior angle of a regular n-gon is given by:

$\dfrac{360\degree}{n}$

We have:

n=11

Hence, the measure of each exterior angle is given by:

$\dfrac{360}{11}\\\\\\=32.7272$

Hence, to the nearest degree the measure of the exterior angle is: 33°

Alex73 [517]3 years ago

7 0

Answer: 33°

Explanation:

360 ÷ 11 = 33 (nearest degree)

The Wise Orange knows that exterior angles always sum up to 360°

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Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$