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Zanzabum
2 years ago
12

Explain why the two figures below are not similar. Use complete sentences and provide evidence to support

Mathematics
1 answer:
Andreas93 [3]2 years ago
8 0

Answer:

they are not like terms

Step-by-step explanation:

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The product of 8 and a number algebraic expression
dybincka [34]

Answer: 8x

Step-by-step explanation:

Product stands for multiplication, so we need to use (×)

Let x = the number.

----------------------------------------------

The product of 8 and a number

8 × x=8x

3 0
3 years ago
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Which pair of polygons is similar
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I didn’t see an image or anything but I looked it up and it said regular polygons, since they have the sides all the same length they must always be in the same proportions, and their interior angles are always the same.
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2 years ago
Find the surface of the prism
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Answer:

no se podrías resolverlo tu

6 0
2 years ago
Please help me with 1-4. I will give an Brainly and a bunch of extra points.
xz_007 [3.2K]

Answer:

\sf 1) \quad \sf A \cup C = \{a, b, c, d, e\}

\sf 2) \quad B \cap A = \{a, b, d\}

\sf 3) \quad B' = \{c, f, g, h \}

\sf 4) \quad A -(B \cap C') = \{a, c \}

Step-by-step explanation:

<u>Set Notation</u>

\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}

Given sets:

  • U = {a, b, c, d, e, f, g, h}
  • A = {a, b, c, d}
  • B = {b, e, a, d}
  • C = {a, e}

Therefore:

  • Universal set = {a, b, c, d, e, f, g, h}
  • B' = not in B = {c, f, g, h}
  • C' = not in C = {b, c, d, f, g, h}

<u>Question 1</u>

\begin{aligned}\sf A \cup C & = \sf \{a, b, c, d\} \cup \{a,e\}\\& = \sf \{a, b, c, d, e\}\end{aligned}

<u>Question 2</u>

\begin{aligned}\sf B \cap A & = \sf \{b, e, a, d\} \cap \{a, b, c, d\}\\& = \sf \{a, b, d\}\end{aligned}

<u>Question 3</u>

\begin{aligned}\sf B' & = \rm U - \sf B\\& = \sf \{a, b, c, d, e, f, g, h \}-\{b, e, a, d\}\\& = \sf \{c, f, g, h \}\end{aligned}

<u>Question 4</u>

\begin{aligned}\sf A -(B \cap C') & = \sf \{a, b, c, d \}- \left( \{b, e, a, d \} \cap \{b, c, d, f, g, h \} \right)\\& = \sf \{a, b, c, d \}- \{b, d \} \\& = \sf \{a, c \}\end{aligned}

Learn more about set notation here:

brainly.com/question/28353607

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<span>xcos(y) --> For this part, use the product rule, which would mean 
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sinx's derivative is just cosx, so we get as a final answer 

cosy - xsiny * dy/dx - cosx =0 
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dy/dx = cosx - cosy / -xsiny 

When y=0, 
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dy/dx = cosx - cos(0) / -xsin(0) [note: sin(0) =0] 
dy/dx = undefined [since you can't divide by 0]</span><span>
</span>
6 0
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