1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ierofanga [76]
3 years ago
15

The frequency of a hum that is generated by an engine is 270hz. If t starts at zero, which of the following would best describe

this frequency over time?
(Don’t pay attention to the answer chosen)

Mathematics
1 answer:
IceJOKER [234]3 years ago
6 0

Answer:

sin ( 2π(270)*t )

Step-by-step explanation:

Solution:-

- The frequency of the hum is denoted as k = 270 Hz.

- The displacement of the hum is modeled by a sinusoidal function.

- The trigonometric modelling of frequency generating systems is given in the following general form:

                               sin ( w*t ) + c

- Where,

              A: The amplitude of displacement e

              w: The angular speed of the hum

              c : The initial condition of displacement.

- Here, we will assume A = 1 and c = 0. The hum starts from time t = 0 seconds.

- The angular speed is the unit of speed that denotes the number of cycles in radians are undergone by the frequency generator device/person in unti time t.

- The angular speed is given by the following relation:

                             w = 2πk

                             w = 2π(270).

- The general model of the hum would be:

                             sin ( 2π(270)*t )

             

You might be interested in
He coordinates of the vertices of △JKL are J(3, 0) , K(1, −2) , and L(6, −2) . The coordinates of the vertices of △J′K′L′ are J′
Deffense [45]
Check the picture:

Rotating JKL 180° with respect to the origin, and translating it 1 unit up, we get J'K'L'.

That is, the 2 triangles match perfectly.


Answer: 
<span>△JKL is congruent to △J′K′L′ because you can map △JKL to △J′K′L′ using a rotation of 180° about the origin followed by a translation 1 unit up, which is a sequence of rigid motions.</span>

3 0
3 years ago
Read 2 more answers
A simple random sample from a population with a normal distribution of 98 body temperatures has x =98.90 °F and s =0.68°F. Const
Ludmilka [50]

Answer:

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

Step-by-step explanation:

1) Data given and notation  

s=0.68 represent the sample standard deviation  

\bar x =98.90 represent the sample mean  

n=98 the sample size  

Confidence=90% or 0.90  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .  

2) Calculating the confidence interval  

The confidence interval for the population variance is given by the following formula:  

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}  

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:  

df=n-1=98-1=97  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,97)" "=CHISQ.INV(0.95,97)". so for this case the critical values are:  

\chi^2_{\alpha/2}=120.990  

\chi^2_{1- \alpha/2}=75.282  

And replacing into the formula for the interval we got:  

\frac{(97)(0.68)^2}{120.990} \leq \sigma \leq \frac{(97)(0.68)^2}{75.282}  

0.371 \leq \sigma^2 \leq 0.596  

Now we just take square root on both sides of the interval and we got:  

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

3 0
3 years ago
How do I convert a mixed number to a improper number
sammy [17]
You multiply the denominator by the whole number then add the numerator. example: 2 2/5= 12/5
7 0
3 years ago
Read 2 more answers
The length of a perpendicular drawn from a point(a,3) on the line is 4.Find the value of a.​
VladimirAG [237]

Answer:

a = 1 or = -37/3

Step-by-step explanation:

refer to the attachment !

8 0
3 years ago
A=2 B=3 C=2.5<br><br><br><br> 2a times positive C
Ierofanga [76]

A = 2

So 2 x 2 is 4

C = 2.5

So 4 x 2.5 = 10

8 0
3 years ago
Read 2 more answers
Other questions:
  • <img src="https://tex.z-dn.net/?f=-8%3D%5Cfrac%7Bx%2B11%7D%7B-2%7D" id="TexFormula1" title="-8=\frac{x+11}{-2}" alt="-8=\frac{x+
    10·2 answers
  • Find the missing angle please!!
    9·1 answer
  • What is .09 in words
    5·1 answer
  • 6x-3y=-9 to slope intercept form
    12·2 answers
  • I need help!!! Please help me cuties<br> REPORTING LINKS!!
    14·2 answers
  • 8. At a music festival 55% of the crowd are from the UK, 25% are from elsewhere in Europe
    12·2 answers
  • What is the mesuement for y
    9·1 answer
  • A line passes through tge points (1,-3) and (4,6) what is the zero of this line ?
    15·1 answer
  • 3. The ratio of blue marbles to white marbles in Simran’s bag is equal to
    14·2 answers
  • If m = 14 and n = 4, what is the value of the following expression?<br> m - 2 • n + 3
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!