Answer:
t=3.5 seconds
Step-by-step explanation:
Given
h(t) = −16t^2 + 111t + 0
h'(t)= -32t + 111
Maximum height occurs when h(t) = 0 and the ball begins to fall
h(t)= -32t + 111=0
-32t + 111=0
-32t=-111
Divide both sides by -32
t=3.46872
Approximately, t=3.5 seconds
Recall,
Maximum height occurs when h(t) = 0
h(t)= -32t + 111=0
= -32(3.46872)+111
= -110.99904+111
= 0.00096 ft
Midday is 12pm so you add whatever hours to that. Which is 1:20pm after midday (12pm)
Answer:
Step-by-step explanation:
you multiple each hight and base
Answer:
You post the MCP problems here? Lol
Step-by-step explanation:
haha
ill tell mr aram someday ;p
D.). I think. yeah because 2 side are equal and 1 isn't.
