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nlexa [21]
2 years ago
5

Sarah, Melissa, Ben, Jennifer, and Lisa like to sing duets. How many different possible pairs that could sing together from this

group?​
Mathematics
2 answers:
Illusion [34]2 years ago
8 0

Answer:

10 different duets

Step-by-step explanation:

S = Sarah

M = Melissa

B = Ben

J = Jennifer

L = Lisa

(Without repeating)

S + M

S + B

S + J

S + L

M + B

M + J

M + L

B + J

B + L

J + L

uranmaximum [27]2 years ago
4 0
I’m pretty sure it 10 :) I hope I’m right if not then I’m really sorry for wasting your time. Hope you have a nice day :)
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Can someone answer theese 3 questions.
NNADVOKAT [17]

Answer:

1.) A

2.) D

3.) A

Step-by-step explanation:

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2 years ago
I need to know if this Answer is correct. please tell me the answer. if it's wrong. Thanks!!!
yaroslaw [1]
Here, as I can see, you are adding fractions, and making sure you have a common denominator. 

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2 years ago
Read 2 more answers
2) Juan had $622 in his checking account. He deposited a check for $180, and $100
adoni [48]

Answer:

867

Step-by-step explanation:

622+180+100=902

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3 0
2 years ago
-2*f(6-)-7*g(-7)= ???
const2013 [10]

Answer:

12f+49g

Step-by-step explanation:

-2f(-6)-7g(-7)\\12f+49g

5 0
3 years ago
Read 2 more answers
Sort each equation according to whether it has one solution, infinitely many solutions, or no solution.
Sedaia [141]

Answer:

Equations with one solution: -2(x-3) = 2x-6

Equations with no solution:

6(x+5) = 6x+11\\5(x-2) = 5x-7

Equations with infinite many solutions: -3(x-4) = -3x+12

Step-by-step explanation:

We will solve each equation to see if it has one solution, no solution or infinite many solutions.

An equation where the value of variable can be found has one solution.

An equation with no solution has both sides different.

An equation with infinite solution will have both sides equal after solution(number)

So,

<u>Equation 1:</u>

5(x-2) = 5x-7

5(x-2) = 5x-7\\5x-10 = 5x-7\\5x-5x = -7+10\\0 = 3

As both sides are not equal, equation has no solution.

<u>Equation 2:</u>

-3(x-4) = -3x+12\\-3x+12 = -3x+12\\-3x+3x = -12+12\\0=0\\

As both sides are equal the equation has infinite many solutions.

<u>Equation 3:</u>

-2(x-3) = 2x-6\\-2x+6 = 2x-6\\-2x-2x = -6-6\\-4x = -12\\\frac{-4x}{-4} = \frac{-12}{-4}\\x = 3

As x=3, the equation has only one solution.

<u>Equation 4:</u>

6(x+5) = 6x+11\\6x+30 = 6x+11\\6x-6x+30 = 11\\30 =11

The equation has no solution.

Hence,

Equations with one solution: -2(x-3) = 2x-6

Equations with no solution:

6(x+5) = 6x+11\\5(x-2) = 5x-7

Equations with infinite many solutions: -3(x-4) = -3x+12

6 0
2 years ago
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