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Crazy boy [7]
3 years ago
11

It rained 0.72 inches on Monday and 1.6 inches on Tuesday. How much more did it rain on Tuesday than Monday?

Mathematics
2 answers:
Whitepunk [10]3 years ago
8 0

Answer:

.88

Step-by-step explanation:

You just need to subtract the 2 values or 1.6-0.72

valentinak56 [21]3 years ago
6 0

Answer:

0.88

Step-by-step explanation:

1.6-0.72=0.88

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Leela made goody bags for her party and put 5 pieces of candy in each bag. She bought gummies and chocolates yo put in het goody
slavikrds [6]

Answer:

4 ways

Step-by-step explanation:

1 gummy 4 chocolates

2 gummy 3 chocolates

3 gummy 2 chocolates

4 gummy 1 chocolates

This is what i think the answer is hope it helps

5 0
3 years ago
Find the area bounded by y=ln x, x=2, x=4 and the x-axis.​
Advocard [28]

4 sq.units

area of a rectangle = length × breadth

length = 4units

breadth = 1units

A = l × b

= 4 × 1

= 4 sq.units

<h3><em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELPS</em><em> </em><em>U</em><em> </em></h3>

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8 0
3 years ago
If ABCD is an A4 sheet and BCPO is the square, prove that △OCD is an isosceles triangle. And find the angles marked as 1 to 8 wi
Dmitry [639]

Answer:

The diagram for the question is missing, but I found an appropriate diagram fo the question:

Proof:

since OC = CD = 297mm Therefore, Δ OCD is an isoscless triangle

∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

∠DOP = 22.5°

∠PDO = 67.5°

∠ADO = 22.5°

∠AOD = 67.5°

Step-by-step explanation:

Given:

AB = CD = 297 mm

AD = BC = 210 mm

BCPO is a square

∴ BC = OP = CP = OB = 210mm

Solving for OC

OCB is a right anlgled triangle

using Pythagoras theorem

(Hypotenuse)² = Sum of square of the other two sides

(OC)² = (OB)² + (BC)²

(OC)² = 210² + 210²

(OC)² = 44100 + 44100

OC = √(88200

OC = 296.98 = 297

OC = 297mm

An isosceless tringle is a triangle that has two equal sides

Therefore for △OCD

CD = OC = 297mm; Hence, △OCD is an isosceless triangle.

The marked angles are not given in the diagram, but I am assuming it is all the angles other than the 90° angles

Since BC = OB = 210mm

∠BCO = ∠BOC

since sum of angles in a triangle = 180°

∠BCO + ∠BOC + 90 = 180

(∠BCO + ∠BOC) = 180 - 90

(∠BCO + ∠BOC) = 90°

since ∠BCO = ∠BOC

∴  ∠BCO = ∠BOC = 90/2 = 45

∴ ∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

For ΔOPD

Tan\ \theta = \frac{opposite}{adjacent}\\ Tan\ (\angle DOP) = \frac{87}{210} \\(\angle DOP) = Tan^-1(0.414)\\(\angle DOP) = 22.5 ^{\circ}

Note that DP = 297 - 210 = 87mm

∠PDO + ∠DOP + 90 = 180

∠PDO + 22.5 + 90 = 180

∠PDO = 180 - 90 - 22.5

∠PDO = 67.5°

∠ADO = 22.5° (alternate to ∠DOP)

∠AOD = 67.5° (Alternate to ∠PDO)

3 0
3 years ago
Sara was making slug slime soup for her six friends. She needed 0.06
Marina86 [1]

Answer:

0.01

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Step-by-step explanation:

3 0
3 years ago
If n is the term, what is the first integer value of n where the sequence 2n² is greater than 50?
Nezavi [6.7K]

Answer:

The 6th term is first integer value of n greater then 50 in the 2n^2 sequence.

Step-by-step explanation:

2n^2 sequence:

2,8,18,32,50,72

3 0
3 years ago
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