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Usimov [2.4K]
3 years ago
7

What is 3/4 of 4/5= ​

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0

Answer:

answer: 15/16 Hope this helps!

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13 million<br> in scientific notation
amm1812
13,000, 000 is the correct answer
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3 years ago
Which graph represents functions f and g?
igor_vitrenko [27]
The answer is C because it’s the only answer that could be correct.
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3 years ago
Consider two x distributions corresponding to the same x distribution. The first x distribution is based on samples of size n =
Tanya [424]

Answer:

The distribution with n = 225 will give a smaller standard error.

Since sigma x = sigma/√n, dividing by the square root of 225 will result in a small standard error regardless of the value of sigma.

Step-by-step explanation:

Standard error is given by standard deviation (sigma) divided by square root of sample size (√n).

The distribution with n = 225 would give a smaller standard error because the square root of 225 is 15. The inverse of 15 multiplied by sigma is approximately 0.07sigma which is smaller compared to the distribution n = 100. Square of 100 is 10, inverse of 10 multiplied by sigma is 0.1sigma.

0.07sigma is smaller than 0.1sigma

8 0
4 years ago
Circle A has an area of 452.16 ft^2 with a radius of 12 ft. If circle B has a radius of 17 ft, what is its area?
Dmitry [639]
To find this answer, you would need to use the equation for area of a circle, or in this case, a=3.14x289, since 3.14 is pi and 289 is your radius squared. giving you a final answer of 907.46 feet squared.
5 0
3 years ago
Can someone please help me with this
Inessa05 [86]
To find the area of a prism, you calculate the area of the cross-section and multiply that number by the length. The cross-section of this prism is a trapezium, and the formula for this is \frac{a+b}{2}h. 
Insert your given numbers to find out the area of this prism's cross-section:
\frac{3+12}{2}12=90
Now, multiply 90 by the length, 10cm, to find out the volume of the prism;
90×10=900cm³
Therefore, your answer id the third option.

6 0
4 years ago
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