From the function y=x^2-4x+7
to complete the square we proceed as follows:
The vertex form is given by:
y=(x-h)^2+k
where (h,k) is the vertex:
thus from the function we shall have:
y=x^2-4x+7
c=(b/2a)²
c=(4/2)²=4
thus adding an subtracting 4 in the expression:
y=x^2-4x+4-4+7
y=(x-2)^2+3
thus the vertex will be:
(2,3)
The answer is:
<span>D. Minimum at (2, 3)</span>
Answer:
with what exactly
Step-by-step explanation:
<h3><u>Answer:</u></h3>
- First term = 6
- Common difference= 4
<h3><u>Solution</u><u>:</u></h3>
Let's take the first term as <u>a</u> and the common difference be <u>d</u>
The formula to find the nth term of an arithmetic progression is given by :
<u>According to question, we have :</u>
- 16th term of an AP is three times the 5th term.
➝ a16 = 3 ( a5 )
➝ a + ( 16 - 1 )d = 3 ( a + ( 5 - 1 )d )
➝ a + 15d = 3 ( a + 4d )
➝ a + 15d = 3a + 12d
➝ 15d - 12d = 3a - a
➝ 3d = 2a
➝ 2a = 3d
➝ <u>a = 3d/2</u><u></u>ㅤㅤㅤ⸻ ( 1 )
- And, the 12th term is 20 more the 7th term.
➝ a12 - ( a7 ) = 20
➝ a + ( n - 1 )d -( a + ( n - 1 )d ) = 20
➝ a + ( 12 - 1 )d - + a + ( 7 - 1 )d ) = 20
➝ a + 11d - ( a + 6d ) = 20
➝ a - a + 11d - 6d = 20
➝ 5d = 20
➝ d = 20/ 5
➝<u> d = 4</u>
- <u>Using</u><u> equation</u><u> (</u><u> </u><u>1</u><u> </u><u>)</u>
➝ a = 3d / 2
➝ a = ( 3 × 4 ) / 2
➝ a = 12 / 2
➝<u> a = 6</u>
