120º is 1/3 of a complete revolution of 360º. So the area of this sector should be 1/3 the area of the complete circle.
A circle with radius 9 has area 9^2 π = 81π.
So the sector has area 81π/3.
Put another way: The area <em>A</em> of a circular sector and its central angle <em>θ</em> (in degrees) occur in the same ratio as the area of the entire circle with radius <em>r</em> according to
<em>A</em> / <em>θ </em>º = (π <em>r </em>^2) / 360º
==> <em>A</em> = π/360 <em>θ r</em> ^2
In this case, <em>r</em> = 9 and <em>θ</em> = 120º, so
<em>A</em> = π/360 * 120 * 81 = 81π/3
Answer:x
2−14x+40=0 Factor x2−14x+40 using the AC method.(x−10)(x−4)
0 If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.x−10=0x−4=0 Set the first factor equal to 0 and solve.x=10Set the next factor equal to 0and solve....x=4
The final solution is all the values that make (x−10)(x−4)=0 true x=10,4
Step-by-step explanation:IDK
Answer:
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Step-by-step explanation:
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