$\text{To factor out the expression, all of the numbers have to have the same}\\\text{amount of variables}\\\\\text{You would see that in the expression}\,\, x^3 + 3x^2 + 2x\,\,\text{they all}\\\text{have "x"}\\\\\text{Factor out x:}\\\\x^3 + 3x^2+2x\\\\x(x^2+3x+2)\\\\\text{Factor}\,\, x^3 + 3x^2+2x\\\\x(x+1)(x+2)\\\\\boxed{\text{Answer:}\,x(x+1)(x+2)}}$

6 0

3 years ago

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At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean

GarryVolchara [31]

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean. Draw a normal curve and mark these speeds. 115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145. This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area: normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573. In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

8 0

3 years ago

Plz helppp me right now

____ [38]

Answer:

Step-by-step explanation:Because it's c.

6 0

3 years ago

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