Answer: Probability that she attended class regularly given that she receives A grade is 0.9286.
Step-by-step explanation:
Since we have given that
Probability of those who attend regularly receive A's in the class = 35%
Probability of those who do not regularly receive A's in the class = 5%
Probability of students who attend class regularly = 65%
We need to find the probability that she attended class regularly given that she receives an A grade.
Let E be the event of students who attend regularly.
P(E) = 0.65
And P(E') = 1-0.65 = 0.35
Let A be the event who attend receive A in the class.
So, P(A|E) = 0.35
P(A|E') = 0.05
So, According to question, we have given that
Hence, Probability that she attended class regularly given that she receives A grade is 0.9286.
Answer:
Step-by-step explanation:
To start, we need to find our slope!
We have two points, (-5, -4) and (0,-7).
We can see that our line has to go down 3 and right 5.
Because the line is going down and right, we will have a negative slope.
Using the slope formula , we can input our trackings and have a slope of .
Next, we need to find our y-intercept, which is where the line crosses the y-axis. As it crosses the y-axis at -7, -7 is our y-intercept!
Now we can plug our data into slope-intercept form, y=mx+b!
Answer:
12/18.
Step-by-step explanation:
You have to multiply or divide them both by the same number and keep the order right. If I multiplied both by 3, I might get 18/27, which is equivalent. If I divided both by 3, I might get 2/3, which is also equivalent.
<span>0.75x + 0.5y = 25,
if x=0, </span>⇒0.5y = 25, ⇒y=50
answer: 50 cherry candies
So, there are two equations.
5a + 3c = 30
a + c = 8, therefore, a = 8 - c
5a + 3c = 30
5(8 - c) + 3c = 30
40 - 5c + 3c = 30
-2c = -10
c = 5 , So a = 3