Answer:
9x^4-25x^2+16
Step-by-step explanation:
(x^2−1)(3x−4)(3x+4)=(*)
(x^2−1)((3x)^2−4^2) =
(x^2 - 1)(9x^2-16)=
x^2*9x^2 - x^2*16 - 1*9x^2 +16=
9x^4-16x^2-9x^2+16=
9x^4-25x^2+16
(*) (A-B)(A+B) =A^2 - B^2
Answer:
Step-by-step explanation:
Used:
It appears that you have a derivative and want to integrate...
dy/dx=1+3√x
y(x)=x+(2/3)x^(3/2)+C you are given that f(4)=25 so we can solve for the constant of integration...
y(4)=25=4+16/3+C
21=16/3+C
(63-16)/3=C
47/3=C so
f(x)=x+(2/3)x^(3/2)+47/3
f(x)=(3x+2x^(3/2)+47)/3
Answer:
7
Step-by-step explanation:
The first step to solve this problem is to convert 1h 30min into just minutes. since there are 60 minutes in 1 hour you take 60 and add it ot the 30 extra minutes to get a total of 90.
Now, this question is asking you to find how many calories <u>per</u> minute she burns. When you are asked to find ___ per___ all you have to do is divide the first number by the second one. In this case you will divide calories by minutes.
630/90=<u>7</u>
