Hi the answer to your question is
((3y - 3.5) / (3y + 6)) * 25.5 = (17
/ 25.5) * 25.5
((3y - 3.5) / (3y + 6)) * 25.5 = 17
(76.5y - 89.25) / (3y + 6) = 17
((76.5y - 89.25) / (3y + 6)) * (3y +
6) = 17 * (3y + 6) 76.5y - 89.25 = 51y + 102 76.5y - 51y = 102 + 89.25
25.5y = 191.25
y = 191.25 / 25.5
<span>y = 7.5</span>
Answer:
20
Step-by-step explanation:
(8 * 5) / 2
=> 40/2
=> 20
Answer:
693 fish
Step-by-step explanation:
In 10 years, we can tell that the amount of fish increased by 1.833...(990 divided by 540) times. If we divide 1.833... by 10, we can find how much the pond increases by yearly. we get 0.1833... If we multiply that by 7 (because the gap between 1986 and 1979 is 7 years), we get 1.2833... So, if we multiply 540 by 1.28333..., we get 693 fish.
Alright, so the sum of two days is going to equal zero.
The variable here is what Jesse got on the first day. Let's call it "x".
x-6=0
x is the first day's score, -6 is the second day's score, and the total score is zero.
Now, add 6 to both sides.
x-6=0
+6 +6
x=6
Jesse's score for the first day was (+)6.
