Answer:
306.8 feet
Step-by-step explanation:
Refer the attached figure .
A surveyor moves 160 feet away from the base of the pole i.e. ED = 160 m
Referring the image .
AC=ED=160 m
A transit i.e. AE is 6 feet tall.
AE = CD=6 feet
With a transmit the angle of elevation to the top of the pole to be 62° i.e. ∠BAC = 62°
To Find BC , use tigonometric ratio.
Now, the height of the pole = BC+CD =300.8+6=306.8 feet
Hence the height of the pole is 306.8 feet
Answer:
Input variable x: Number of classes he attends.
Output variable y: Monthly cost
Slope: Cost per class, of $2
y-intercept: Membership fee, of $25.
Function:
Step-by-step explanation:
This situation can be represented by a function is the following format:
In which y is the monthly cost(output), m is the cost per class(slope), x is the number of classes he attends(input) and b is the membership fee(y-intercept).
We have that:
There is a membership fee of $25 per month and a fee of $2 per workout class he attends.
This means that . So
Answer:
6.06 x
Step-by-step explanation:
(5.25 x ) / (8.7 x
)
= (5.25 x ) x(
)/ (8.7 )
= (5.25 x )/ (8.7 )
= 0.606 x
= 6.06 x
Step-by-step explanation:
1) Subtract 2 from both sides.
2) Simplify 6 - 2 to 4.
3) Divide both sides by 2.
4) Simplify 4/2 to 2.
Therefor, the answer is, d >2.