Please help ASAP!!!??
1 answer:
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Answer:
<h2>The last costumers got 2.25 kilograms of chocolate candies.</h2>Step-by-step explanation:
The question is
<em> There is 11.73 kg of chocolate candies in the grocery store. The first customer bought 48 dag of candies. A second customer bought 4/5 of the remaining quantity. The last three customers bought the same amount of candy. How much chocolate did the last customers get?</em>
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Givens
- The total amount of chocolate candies is 11.73 kilograms.
- First costumer bought 48 dag of candies. (1 kg equals 100 dags)
- Second costumer bougth 4/5 of the remaining.
- Another three costumers bought the same amount of candy.
Let's transform 48 dag to kilograms.
Therefore, the first costumer bought 0.48 kilograms of candies.
The remaining amount is:
Now, we need to multiply the remaining amount of candies with 4/5
Therefore, the second costumer bought 9 kilograms of chocolate candies.
At last, we need to find the new remaining part of candies, which is
Therefore, the last costumers got 2.25 kilograms of chocolate candies.
Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10
10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7
