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3 years ago

Find the 12th and 37th term for each arithmetic sequence.

Mathematics

1 answer:

shutvik [7]3 years ago

5 0

Answer:

3. f(12) = -10; f(37) = -60

4. f(12) = -102; f(37) = -352

Step-by-step explanation:

3. Put the numbers in the formula and do the arithmetic:

f(12) = 12 -2(12-1) = 12 -22 = -10

f(37) = 12 -2(37-1) = 12 -72 = -60

4. The explicit formula for an arithmetic sequence with first term a1 and common difference d is ...

an = a1 +d(n -1)

Your sequence has a first term a1=8 and a common difference d=-10.

As above, fill in the numbers and do the arithmetic.

f(12) = 8 -10(12 -1) = -102

f(37) = 8 -10(37-1) = -352

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3 years ago

Write the ratio in its simplest form:<br> 48mm : 6m

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Find the slope.<br> y = -9x +4<br> m<br> [?]

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Answer:

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3 years ago

find the probability of at least 6 failures in 7 trials of a binomial experiment in which the probability of success in any tria

prohojiy [21]

Answer:

0.8746 = 87.46% probability of at least 6 failures in 7 trials.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

7 trials

This means that $n = 7$

The probability of success in any trial is 9%?

So the probability of a failure is 100 - 9 = 91%, which means that $p = 0.91$

Probability of at least 6 failures in 7 trials?

This is:

$P(X \geq 6) = P(X = 6) + P(X = 7)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{7,6}.(0.91)^{6}.(0.09)^{1} = 0.3578$

$P(X = 7) = C_{7,7}.(0.91)^{7}.(0.09)^{0} = 0.5168$

$P(X \geq 6) = P(X = 6) + P(X = 7) = 0.3578 + 0.5168 = 0.8746$

0.8746 = 87.46% probability of at least 6 failures in 7 trials.

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3 years ago