<h3>Answer:</h3>
x/tan(x) is an even function
sec(x)/x is an odd function
<h3>Explanation:</h3>
<em>x/tan(x)</em>
For f(x) = x/tan(x), consider f(-x).
... f(-x) = -x/tan(-x)
Now, we know that tan(x) is an odd function, so tan(-x) = -tan(x). Using this, we have ...
... f(-x) = -x/(-tan(x)) = x/tan(x) = f(x)
The relation f(-x) = f(x) is characteristic of an even function, one that is symmetrical about the y-axis.
_____
<em>sec(x)/x</em>
For g(x) = sec(x)/x, consider g(-x).
... g(-x) = sec(-x)/(-x)
Now, we know that sec(x) is an even function, so sec(-x) = sec(x). Using this, we have ...
... g(-x) = sec(x)/(-x) = -sec(x)/x = -g(x)
The relation g(-x) = -g(x) is characeristic of an odd function, one that is symmetrical about the origin.
It would be the top right
because they are increasing by intervals of 4 each time. it can’t be the others because top left those are increasing by 5, bottom left decreasing by 4, and bottom right decreasing by .5.
Since

is representing the number of gallons of water in the tub, we need to replace

with the number of gallons remaining in the tube to find the time. Fortunately, the problem is telling us just that: 17.8 gallons. The only thing left is replacing that value in the equation, and solve for

to find the time:




We can conclude that after
3 minutes <span>the tub will have 17.8 gallons of water remaining.</span>
I think It's a>-3, maybe.
Answer:
the last one :)
Step-by-step explanation: