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densk [106]
3 years ago
9

18. A lane 180 m long and 5 m wide is to be paved with bricks, of length 20 cm and breadth 150

Mathematics
2 answers:
maksim [4K]3 years ago
6 0

Area of lane=area of rectangle

=180x5=900m²

Area of brick=0.2x0. 15

=0.03m²

No of bricks needed=900/0.03

=30000

Cost of bricks=30000/1000x750

=30x750=22500

Alenkasestr [34]3 years ago
4 0
We indicate with L length of the lane, with l breadth of the lane.

we calculate the area of ​​a lane:
A₁=L×l=180×5=900 m²

we indicate with b length of the brick , with h breadth of the brick.

we calculate the area of a brick:
A₂=b×h=20×150=3000 cm²

we convert the cm² in m² (1m²=10000 cm²)
3000 cm²=0,3 m²
then
A₂=0,3 m²

we calculate the required number of bricks:
n=A₁/A₂=900/0,3=3000 bricks
we calculate the total cost of bricks:
tot=(750×3000):1000=2250 ruppes
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Answer:

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Step-by-step explanation:

The question is not complete, the correct question is given as:

The graph shows information about the speed of a vehicle during the final 50 seconds of a journey.  At the start of the 50 seconds the speed is k metres per second.  The distance travelled during the 50 seconds is 1.35 kilometres.

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The graph is attached. The total time = 50 seconds, total distance = 1.35 km = 1350 m  

a) The average speed is the ratio of the total distance traveled to the total time taken to cover this distance. The average speed is given by the formula:

Average \ speed=\frac{total\ distance}{total\ time}\\ Substituting: \\ Average \ speed=\frac{1350\ m}{50\ s} = 27\ m/s

b) From the graph, the total distance covered is the area of the graph. The graph is made up of a rectangle and triangle, the area of the graph is equal to the sum of area of rectangle and area of triangle.

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Gradient=\frac{change\ in\ speed }{change\ in\ time}=\frac{0-k}{50-40}  \\ bt \ k=30\\Gradient=\frac{0-30}{50-40}= \frac{-30}{10} =-3

ii) Since the gradient is negative it means it is deceleration. That is in the in the last 10 seconds the vehicle decelerates at a rate of 3 m/s²

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