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3 years ago

Name a ray with an endpoint of A.

Mathematics

1 answer:

Tanya [424]3 years ago

3 0

B to A. it passes through E

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How many lines of symmetry does a Pentagon have?

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4 years ago

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Qhat is 4c - 11 - 5c + 17 what are the coefficients

Oksi-84 [34.3K]

Answer:

4 and 5

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4 and 5 are the co efficients of c

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3 years ago

39 less than the product of a number and 13 is 39

Lana71 [14]

Answer:

13n - 39 = 39

Step-by-step explanation:

Let the number be n. Then we have 13n - 39 = 39

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4 years ago

AP CALC 98 POINTS!!!!!!

bekas [8.4K]

Looking at this question again, I don't understand why you're told "for y=11". That doesn't seem relevant at all... So you can disregard the answer I posted a few minutes ago on your other question.

a) With $x^2=-2+y+5\cos y$ , differentiate both sides with respect to $x$ to get

$2x=\dfrac{\mathrm dy}{\mathrm dx}-5\sin y\dfrac{\mathrm dy}{\mathrm dx}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x}{1-5\sin y}$

b) The point P occurs at $x=2$ , which corresponds to a $y$ -coordinate of

$4=-2+y+5\cos y\implies y\approx4.928$

The slope of the line tangent to this point is approximately

$\dfrac{\mathrm dy}{\mathrm dx}\approx\dfrac{2(2)}{1-5\sin(4.928)}\approx0.68$

so the equation of the tangent line is approximately

$y-4.928=0.68(x-2)\implies y=0.68x+3.57$

c) The tangent line to the graphed curve is vertical when $\dfrac{\mathrm dy}{\mathrm dx}$ is undefined. This happens when $1-5\sin y=0$ , or $y=\pi-\sin^{-1}\dfrac15+2n\pi$ and $y=\sin^{-1}\dfrac15+2n\pi$ where $n$ is any integer.

In case you're not sure where the general solution came from: We have

$\sin y=\dfrac15$

which has an infinite number of solutions. $\sin^{-1}\dfrac15$ is one of them, which we obtain by taking the inverse sine of both sides of this equation. Since $\sin(\pi-x)=\sin x$ , we also know that $\pi-\sin^{-1}\dfrac15$ is a solution. And since $\sin(x+2n\pi)=\sin x$ for integers $n$ , we also know that we can add any multiple of $2\pi$ to these two solutions to get infinitely more solutions.

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3 years ago