This kind of experiments are ruled by Bernoulli's formula. If you have probability p of "success", and you want k successes in n trials, the probability is

It's easier to compute the first probability by difference: instead of computing the probability of the event "at least one of the surveyed eats breakfast", let's compute the probability of its contrary: none of them eats breakfast. So, we want 0 successes in 4 trials, with probability of success 0.34. The formula yields

Since the contrary has probability 17%, our event "at least one of the surveyed eats breakfast" has probability 83%.
As for the second question, the event "at least three of the surveyed eats breakfast" is the union of the events "exactly three of the surveyed eats breakfast" and "exactly four of the surveyed eats breakfast". So, we just need to sum their probabilities:

Answer:
90
Step-by-step explanation:
Answer:
-4 ≤ x ≤ 6
Step-by-step explanation:
When we talk of the domain, we are referring to the possible x-values
from the diagram, we can see that we have the x-values at -4 and 6
The dotted line means that -4 and 6 are in the domain
Thus, the two points represent the end and starting point of the domain
Writing this in interval notation, we have the representation as;
-4 ≤ x ≤ 6
Answer:
8.1835
9.85
10.67
Step-by-step explanation:
Answer:
Part A is D and part B is 78
Step-by-step explanation:
for part b 80 x0.35 is 28
28+50 is 78