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Ket [755]
2 years ago
13

Can someone answer this math problem!

Mathematics
1 answer:
mr_godi [17]2 years ago
7 0

Answer:

b i think i am wrong idk

Step-by-step explanation:


You might be interested in
What is the answer to this
Xelga [282]
Lateral area of triangular prism = (a+b+c)h where a, b and c are the sides of the triangular base, h is the height.

LA= (a+b+c)h=
a=4
b=6
c=?
c=9
h=8

c=√6²+4²=√80 or approximately 9

you should get An Area= (4+6+√80)8

LA= 80+8√80


4 0
3 years ago
Can someone plssss answer this.
goblinko [34]
1: B
because a triangle angles all have to add up to 180
8 0
3 years ago
To find 5, Beau found 22 = 4 and 32 = 9. He said that since 5 is between 4 and 9, 5 is between 2 and 3. Beau thinks a good estim
shusha [124]

Complete question

To find \sqrt{5} , Beau found 2^2 = 4 and 3^2 = 9 . He said that since 5 is between 4 and 9, \sqrt{5}, is between 2 and 3. Beau thinks a good estimate for \sqrt{5} , is \frac{2 + 3}{2} =  2.5 Is his estimate high or low? How do you know?

Answer:

The estimation is high because 5 is very close to 4 so \sqrt{5} will also be very close to \sqrt{4} which is lower than the estimate

In order to get a good estimate

The first step is to choose a number between 2 and 3 let say 2.8 , 2,85 , 2.9 and the square them

i.e

2.1^2 =  4.41

     2.2^2 =  4.84

      2.3^2 =  5.29

From here we can see that \sqrt{5}  lies between 2.2 and 2.3 but is closer to  2.2

So a good estimate for \sqrt{5} is 2.2

Step-by-step explanation:

8 0
3 years ago
2. Reece is playing a carnival game in which he
Maslowich
25% or 2/4 and to win one game 50% or 1/2
6 0
3 years ago
How many elements are in the union of five sets if the sets contain 10,000 elements each, each pair of sets has 1000 common elem
masya89 [10]

Answer:

40951

Step-by-step explanation:

Using the principles of inclusion - Exclusion

Where C(n,r)=n!/(n-r)!r!

Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000

Total Number of elements in each pair including number repetition of sets is given as

=(1000) × C(5, 2) =10000

Number of elements in each triple of sets is given as

=(100) × C(5, 3) =1000

Number of elements in every four sets

=(10) × C(5, 4)=50

Number of elements in every one set

(1) × C(5, 5)=1

Therefore total number of unique elements=50000-10000+1000-50+1

=40951

5 0
3 years ago
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